Answer:
6.67 ohm
Explanation:
From the question given above, the following data were obtained:
Resistor 1 (R₁) =20 ohm
Resistor 2 (R₂) = 20 ohm
Resistor 3 (R₃) = 20 ohm
Equivalent Resistance (R) =?
Since the resistors are arranged in parallel connection, the equivalent resistance can be obtained as follow:
1/R = 1/R₁ + 1/R₂ + 1/R₃
1/R = 1/20 + 1/20 + 1/20
1/R = (1 + 1 + 1) / 20
1/R = 3/20
Invert
R = 20/3
R = 6.67 ohm
Therefore, the equivalent resistance is 6.67 ohm.
At the peak of its flight ALL the energy given to the rocket is potential energy (its velocity is zero) and that is calculated as mgh So Energy given to rocket = mgh Energy expended by engine = F x D (D= height where engine stops) Energy 'lost' to drag is the difference between the two values. please if this helped mark it as the brainiest answer.
They do. mostly because they want validation from others
<span>7.21 ft/s^2
Since you're looking for average acceleration, you can simply divide the change in velocity by the time. To make the calculation more reasonable, first convert the speed of 173 mi/h into ft/sec by multiplying by 5280 to convert from mi/h to ft/h and then dividing by 3600 to convert from ft/h to ft/s.
173 * 5280 / 3600 = 253.7333 ft/s
Now divide the change in velocity by the time in seconds.
253.7333 ft/s / 35.2 s = 7.208333 ft/s^2
Rounding result to 3 significant figures gives 7.21 ft/s^2</span>