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kaheart [24]
3 years ago
11

he work function of a certain metal is 1.90 eV. What is the longest wavelength of light that can cause photoelectron emission fr

om this metal? (1 eV = 1.60 × 10-19 J, c = 3.00 × 108 m/s, h = 6.626 × 10-34 J ∙ s)
Physics
1 answer:
bixtya [17]3 years ago
3 0

Answer:

6538.8 Angstrom

Explanation:

work function, w = 1.9 eV = 1.9 x 1.6 x 10^-19 J = 3.04 x 10^-19 J

Let the longest wavelength is λ.

W = h c / λ

λ = h c / W

λ = (6.626 x 10^-34 x 3 x 10^8) / (3.04 x 10^-19)

λ = 6.5388 x 10^-7 m = 6538.8 Angstrom

Thus, the longest wavelength is 6538.8 Angstrom.

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dexar [7]
My answer to the problem is as follows:
 
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Vf = Vi + a*t 

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for b, Vf = 0, Vi = 3.0 m/s, and a = -0.60 m/s/s. 

I hope my answer has come to your help. God bless and have a nice day ahead!
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7 0
2 years ago
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If a star collapses to a tenth its size, gravitation at its surface increases by?
tino4ka555 [31]

If a star collapses to a tenth its size, gravitation at its surface increases by 100 times as much.

The contraction of an astronomical object caused by its own gravity, which tends to pull stuff inward toward the center of gravity, is known as gravitational collapse. A cloud of interstellar matter gradually collapses under the influence of gravity to form a star. The temperature rises as a result of the compression brought on by the collapse until thermonuclear fusion takes place in the star's core. At this point, the collapse gradually comes to an end as the outward heat pressure equalizes the gravitational forces. Following that, the star is in a condition of dynamic equilibrium. A star will repeatedly collapse once all of its energy sources have been used up until it reaches a new equilibrium condition.

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8 0
2 years ago
the car starts from rest at s=0 and increases its speed at at=4m/s^2. Determine the time when the magnitude of acceleration beco
dem82 [27]

Answer:

<em>Time =  5 seconds</em>

<em>Distance = 50 meters</em>

Explanation:

<u>Constantly Accelerated Motion</u>

When the velocity of a moving object changes at a constant rate, called acceleration, the velocity changes in same amounts in the same times. The question has a mistake when asking when the acceleration is 20 m/s. If the acceleration is constant, the only variable that can change to that value is the velocity. The equation to calculate the speed is

v_f=v_o+a.t

And the distance s is

\displaystyle s=v_o.t+\frac{gt^2}{2}

Given the object starts from rest, vo=0 and vf=20 m/s at a=4\ m/s^2. We compute t

\displaystyle t=\frac{v_f-v_o}{a}=\frac{20-0}{4}

\boxed{t=5\ sec}

Now we compute s

\displaystyle s=0+\frac{4\times 5^2}{2}

\boxed{s=50\ m}

5 0
3 years ago
An object with a mass of 5kg accelerates at 2m/s2. How much force in Newtons(N) is needed to cause this to happen??
Reptile [31]

Answer: The formula of Newtons second law of motion is F=MA so therefore it would be written like this Force = Mass X Acceleration

F = 5 x 2

F = 10 N

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I’m confused about this question
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