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kaheart [24]
3 years ago
11

he work function of a certain metal is 1.90 eV. What is the longest wavelength of light that can cause photoelectron emission fr

om this metal? (1 eV = 1.60 × 10-19 J, c = 3.00 × 108 m/s, h = 6.626 × 10-34 J ∙ s)
Physics
1 answer:
bixtya [17]3 years ago
3 0

Answer:

6538.8 Angstrom

Explanation:

work function, w = 1.9 eV = 1.9 x 1.6 x 10^-19 J = 3.04 x 10^-19 J

Let the longest wavelength is λ.

W = h c / λ

λ = h c / W

λ = (6.626 x 10^-34 x 3 x 10^8) / (3.04 x 10^-19)

λ = 6.5388 x 10^-7 m = 6538.8 Angstrom

Thus, the longest wavelength is 6538.8 Angstrom.

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A 1 170.0 kg car traveling initially with a speed of 25.000 m/s in an easterly direction crashes into the back of a 9 800.0 kg t
Stella [2.4K]

Answer:

Explanation:

mass of car, m1 = 1170 kg

mass of truck, m2 = 9800 kg

initial velocity of car, u1 = 25 m/s

initial velocity of truck, u2 = 20 m/s

final velocity of car, v1 = 18 m/s

Let the final velocity of truck is v2.

(a) Use the conservation of momentum

m1 x u1 + m2 x u2 + m1 x v1 + m2 x v2

1170 x 25 + 9800 x 20 = 1170 x 18 + 9800 x v2

29250 + 196000 = 21060 + 9800 v2

v2 = 20.84 m/s

(b) Total kinetic energy before collision,

Ki = 0.5 x 1170 x 25 x 25 + 0.5 x 9800 x 20 x 20

Ki = 365625 + 1960000 = 2325625 J

Total final kinetic energy

Kf = 0.5 x 1170 x 18 x 18 + 0.5 x 9800 x 20.84 x 20.84

Kf = 189540 + 2128097.44

Kf = 2317637.44 J

Change in energy = 2325625 - 2317637.44 = 7987.56 J

(c) It is due to the heat energy

4 0
4 years ago
How does the work needed to lift an object and the gravitational potential energy of an object compare
Ganezh [65]

When you do work to lift the object, the amount of work you do BECOMES the object's gravitational potential energy.  It GETS its potential energy from the work you do to lift it.  They're equal.  You lose it, and the object gains it.  Energy is not created or destroyed.  It's just transferred from you to the object.  

Later, when you DROP the object, GRAVITY does the same amount of work on it, to pull it to the ground.  Again, no energy is created or destroyed.  Every time a force acts to move anything, the energy to do it comes from somewhere, and the energy goes somewhere.

8 0
3 years ago
Consider a magnetic force acting on an electric charge in a uniform magnetic field. Which of the following statements are true?
NISA [10]

Explanation:

The magnetic force acting on the charged particle in magnetic field is given by :

F=qvB\ \sin\theta

Here,

q is the charged particle

v is the speed of particle

B is magnetic field

\theta is the angle between the v and B.

The correct statements for the magnetic force are :

  • An electric charge moving perpendicular to a magnetic field experiences a magnetic force. In this case, \theta=90^{\circ}. It will experience maximum force.
  • The direction of the magnetic force acting on a moving electric charge in a magnetic field is perpendicular to the direction of motion.
  • A magnetic force is exerted on an electric charge moving through a uniform magnetic field.
  • The direction of the magnetic force acting on a moving charge in a magnetic field is perpendicular to the direction of the magnetic field.
8 0
4 years ago
Abdominal breathing is a condition in which only the inferior half of the lungs can be seen expanding and contracting with each
lilavasa [31]

Answer:

The correct answer is - Damage to the nerves that control the diaphragm.

Explanation:

Abdominal breathing is a condition in which inferior half of the lungs can be seen relaxing or contracting and expanding with the breath. This condition occurs due to the various conditions that lead to the respiratory.

It is cause due to the damage to nerves that control the diaphragm. The phrenic nerve is one of the nerve of diaphragm initiates in the neck and passes down.

Thus, the correct answer is - Damage to the nerves that control the diaphragm.

The phrenic nerve is a nerve that originates in the neck (C3–C5) and passes down between the lung and heart to reach the diaphragm.

7 0
3 years ago
Find the torque required for the shaft to transmit 40 kW when (a) The shaft speed is 2500 rev/min. (b) The shaft speed is 250 re
Luba_88 [7]

Answer:

(a) 152.85 Nm

(b) 1528.5 Nm

Explanation:

According to the formula of power

P = τ ω

ω = 2 π f

(a) f = 2500 rpm = 2500 / 60 = 41.67 rps

So, 40 x 1000 = τ x 2 x 3.14 x 41.67

τ = 152.85 Nm

(b) f = 250 rpm = 250 / 60 = 4.167 rps

So, 40 x 1000 = τ x 2 x 3.14 x 4.167

τ = 1528.5 Nm

3 0
3 years ago
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