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2 years ago

The unit of area is a derived unit. Why?

Physics

1 answer:

prohojiy [21]2 years ago

8 0

Explanation:

area=length(m) ×breadth(m) . The unit of area is expressed in terms of fundamental units m^2.thus it is derived unit

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Si el cuerpo no se mueve halle T

Aleks [24]

Well sorry but this is the wrong language.

3 0

2 years ago

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A uniformly charged conducting sphere of 1.1 m diameter has a surface charge density of 6.2 µC/m2. (a) Find the net charge on th

ira [324]

Answer:

(a) q = 2.357 x 10⁻⁵ C

(b) Φ = 2.66 x 10⁶ N.m²/C

Explanation:

Given;

diameter of the sphere, d = 1.1 m

radius of the sphere, r = 1.1 / 2 = 0.55 m

surface charge density, σ = 6.2 µC/m²

(a) Net charge on the sphere

q = 4πr²σ

where;

4πr² is surface area of the sphere

q is the net charge on the sphere

σ is the surface charge density

q = 4π(0.55)²(6.2 x 10⁻⁶)

q = 2.357 x 10⁻⁵ C

(b) the total electric flux leaving the surface of the sphere

Φ = q / ε

where;

Φ is the total electric flux leaving the surface of the sphere

ε is the permittivity of free space

Φ = (2.357 x 10⁻⁵) / (8.85 x 10⁻¹²)

Φ = 2.66 x 10⁶ N.m²/C

8 0

2 years ago

A stone on ground is zero energy

NNADVOKAT [17]

Answer:

A stone on the ground does not have zero energy…there is an internal potential in every object. Aldo is not in action or in any mechanical motion it is being acted upon by gravity and also molecular forces and energy.

Hope this helps !

7 0

3 years ago

How much energy ( in joules ) is released when 0.06 kilograms of mercury is condensed to a liquid at the same temperature ?

aleksley [76]

Answer:

B. 17,705.1 J

Explanation:

The hear released when the mercury condenses into a liquid is given by:

$Q=m \lambda_v$

where

m = 0.06 kg is the mass of the mercury

$\lambda_v$ is the latent heat of vaporization

For mercury, the latent heat of vaporization is $\lambda_v = 296 kJ/kg$ , so the heat released during the process is:

$Q=(0.06 kg)(296 kJ/kg)=17.76 kJ = 17,760 J$

So, the closest option is

B. 17,705.1 J

5 0

3 years ago

Read 2 more answers

If two planets orbit a star, but planet B is twice as far from the star as planet A, planet A will receive ____ times the flux t

Tresset [83]

Answer:

The nearest plant (A) receives 4 times more radiation from the farthest plant

Explanation:

The energy emitted by the star is distributed on the surface of a sphere, whereby intensity received is the power emitted between the area of the sphere

I = P / A

P = I A

The area of the sphere is

A = 4π r²

Since the amount of radiation emitted by the star is constant, we can write this expression for the position of the two planets

P = I₁ A₁ = I₂ A₂

I₁ / I₂ = A₂ / A₁

Suppose index 1 corresponds to the nearest planet,

r2 = 2 r₁

I₁ / I₂ = r₁² / r₂²

I₁ / I₂ = r₁² / (2r₁)²

I₁ / I₂ = ¼

4 I₁ = I₂

The nearest plant (A) receives 4 times more radiation from the farthest plant

7 0

3 years ago