Answer:
The specific question is not stated, however the general idea is given in the attached picture. The electric field in each region can be found by Gauss’ Law.
at r < R:
Since the solid sphere is conducting, the total charge Q is distributed over the surface, and the electric field inside the sphere is zero.
E = 0.
at R < r < 2R:
The electric field can be found by Gauss’ Law as in the attachment. The green pencil shows this exact region.
at 2R < r:
The electric field can again be found by Gauss’ Law, the blue pencil shows the calculations for this region.
Explanation:
Gauss’ Law is straightforward when applied to spheres. The area of the sphere is 
, and the enclosed charge is given in the question as Q for the inner sphere, and 2Q for the whole system.
3.86 m/s^2 is the value of gravity on this large, but low-density, world.
given :
Kepler-12b
diameter= 1.7 times of Jupiter (R_Jupiter = 6.99 × 10^7 m),
mass = 0.43 Jupiter (M_Jupiter = 1.90 × 10^27 kg ).
g = GM/r^2
g = 6.67×10^-11 × 0.43×1.9×10^27/( 1.7×6.99×10^7)^2
g = 3.859 ~ 3.86 m/s^2
Gravity, also referred to as gravitation, is the unchanging force of attraction that binds all matter together in mechanics. It is by far the weakest known force in nature, so it has no effect on determining the internal properties of common matter.
On Earth, everything has weight, or a gravitational pull that is imposed by the planet's mass and proportional to the object's mass. A measure of the force of gravity is the acceleration that freely falling objects experience. At the surface of the Earth, gravity accelerates at a rate of about 9.8 meters per second. As a result, an object's speed increases during free fall by about 9.8 meters per second. At the Moon's surface, a freely falling body accelerates to about 1.6 m/s2.
To know more about gravity visit : brainly.com/question/14428640
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Answer:
It would be the 10 lb ball.
Explanation:
The more that an object weighs, the more force that is needed to accelerate it.
Hope this helped
:)
I think the answer is b, energy.
