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oksano4ka [1.4K]
3 years ago
7

A machine gun fires 50-g bullets at the rate of 4 bullets per second. The bullets leave the gun at a speed of 1000 m/s. What is

the average recoil force experienced by the machine gun?
Physics
1 answer:
TEA [102]3 years ago
5 0

Answer:

Average recoil force experienced by machine will be 200 N

Explanation:

We have give mass of each bullet m = 50 gram = 0.05 kg

There are 4 bullets

So mass of 4 bullets = 4×0.05 = 0.2 kg

Initial speed of the bullet u = 0 m/sec

And final speed of the bullet v = 1000 m/sec

So change in momentum P=m(v-u)=0.2\times (1000-0)=200kgm/sec

Time is given per second so t = 1 sec

We know that force is equal to rate of change of momentum

So force will be equal to F=\frac{200}{1}=200N

So average recoil force experienced by machine will be 200 N

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Answer:

A) μ = A.m²

B) z = 0.46m

Explanation:

A) Magnetic dipole moment of a coil is given by; μ = NIA

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Area = πd²/4 = π(0.05)²/4 = 0.001963

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B) The magnetic field at a distance z along the coils perpendicular central axis is parallel to the axis and is given by;

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Thus,

z = [ (4π x 10^(-7)•2.36)/(2π•5 x 10^(-6))]^(⅓)

Solving this gives; z = 0.46m =

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