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11Alexandr11 [23.1K]
3 years ago
9

Some students want to calculate the work done by friction as an object with unknown mass moves along a straight line on a rough

horizontal surface. The students have a force probe, a meterstick, and a stopwatch. Which of the following will allow lo lake the measurements needed to calculate the work done by friction?
(A) Pulling the block at an unknown constant acceleration with the force probe for a measured time.
(B) Pulling the block at an unknown constant speed with the force probe for a measured time.
(C) Pulling the block at an unknown constant acceleration with the force probe for a measured distance.
(D) Pulling the block at an unknown constant speed with the force probe for a measured distance.
Physics
1 answer:
goblinko [34]3 years ago
3 0

Answer:

(C) Pulling the block at an unknown constant acceleration with the force probe for a measured distance.

Explanation:

As we know that work done is defined by the product of force and displacement

so it is given as

W = F. d

so here in order to find the work done we must know that force and displacement both

so we must have to pull the block with uniform acceleration and then we need to measure the distance to find the work done

so correct answer will be

(C) Pulling the block at an unknown constant acceleration with the force probe for a measured distance.

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The area of a triangle is found by multiplying the height of the triangle by the length of the base and dividing them both by 2. The length of the shorter side in the equation is useless information, so just multiply 39 by 25 and divide that by 2. A=487.5 sq ft. Also, that's a pretty big kite. 
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3 years ago
A 300 g glass thermometer initially at 23 ◦C is put into 236 cm3 of hot water at 87 ◦C. Find the final temperature of the thermo
DIA [1.3K]

Answer:

74^{\circ} C

Explanation:

We are given that

Mass of glass,m=300 g

T_1=23^{\circ}

Volume,V=236cm^3

Mass of water=density\times volume=1\times 236=236 g

Density of water=1g/cm^3

Temperature of hot water,T=87^{\circ}

Specific heat of glass,C_g=0.2cal/g^{\circ}C

Specific heat of water,C_w=1 cal/g^{\circ}C

Q_{glass}=m_gC_g(T_f-T_1)=300\times 0.2(T_f-23)

Q_{water}=m_wC_w(T_f-T)=236\times 1(T_f-87)

Q_{glass}+Q_{water}=0

300\times 0.2(T_f-23)+236\times 1(T_f-87)

60T_f-1380+236T_f-20532=0

296T_f=20532+1380=21912

T_f=\frac{21912}{296}=74^{\circ} C

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3 years ago
Hello please help i’ll give brainliest
maw [93]

Answer:mountains

Explanation:

8 0
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2. What kinds of statistics are used in sports? In a paragraph explain your answer with examples
Lostsunrise [7]

Answer: Sports Illustrated noted that analytics in a sport such as a football is widely used to manage injury prevention. Basketball coaches make use of statistics such as field-goal attempts, effective field goal percentage, free throw attempts, and free throw percentages.

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The measure of a spring’s resistance to being compressed or stretched is the
larisa86 [58]

<u>Answer;</u>

<em>Spring constant </em>

<u>Explanation;</u>

The measure of a spring’s resistance to being compressed or stretched is the <u>spring constant</u>.

  • The symbol of spring constant is K, since it is a constant. From the Hooke's law,for a helical spring or any elastic material, the extension force is directly proportional to the extension provided the elastic limit is not exceeded.
  • Therefore; the spring constant = Force/extension. That is; K = F/e; where k is the spring constant, F is the extension force and e is the extension.
  • Spring constant depicts the resistance of the spring to compressional and stretching forces.
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3 years ago
Read 2 more answers
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