Since f=m(v^2/r),or fnet is equal to ma.
force = unknown
velocity=22m/s
radius=75m
f=m(v^2/r)
f=925(22^2/75)
f=5969.333N
Complete question
A cannon with a muzzle velocity of 500. meters per second fires a cannonball at an angle of 30.° above the horizontal. What is the vertical component of the cannonball's velocity as it leaves the cannon?
A 0.0 m/s
B 250. m/s
C 433 m/s
D 500. m/s
Answer:
The correct option is C
Explanation:
From the question we are told that
The velocity is 
The angle is 
Generally the vertical component of the canon ball is mathematically represented as
=> 
=> 
Answer:
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Explanation:
False because if it already has speed it means it was already accelerated and is now getting slower
Answer:
The intended goal is to increase the brightness of the LED, as light decreases. The LED should be completely off when the light level is high. When I built the circuit, I was very surprised to find out that it functioned in the COMPLETE OPPOSITE way. When I pointed the LDR towards a light source, it increased the brightness of the LED as it turned closer to the light source. If I put my finger on the LDR so that almost no light can enter, the LED looks as if it is completely off. Why is this happening? I suspect it has something to do with the voltage divider, whose output is connected to the base of the 2n3904.
Explanation:
