Answer:
Moreover, Boss says that even if Jupiter is proven to have a core, the planet still could have formed that core through disk instability. Enough dust could have collected and cemented together in the dense gas to form a core many times larger than the size of the Earth.
Explanation:
The same is true of most other objects in the solar system — except Jupiter. The gas giant is so big that it pulls the center of mass between it and the sun, also known as the barycenter, some 1.07 solar radii from the star's center — which is about 30,000 miles above the sun's surface.
69,911 km
69,911 kmJupiter/Radius
Answer:
5.5 km
Explanation:
First, we convert the distance from km/h to m/s
910 * 1000/3600
= 252.78 m/s
Now, we use the formula v²/r = gtanθ to get our needed radius
making r the subject of the formula, we have
r = v²/gtanθ, where
r = radius of curvature needed
g = acceleration due to gravity
θ = angle of banking
r = 252.78² / (9.8 * tan 50)
r = 63897.73 / (9.8 * 1.19)
r = 63897.73 / 11.662
r = 5479 m or 5.5 km
Thus, we conclude that the minimum curvature radius needed for the turn is 5.5 km
Answer:
The charge on the third object is − 21.7nC
Explanation:
From Gauss's Law
Φ = Q/ε₀
where;
Φ is the total electric flux through the shell = − 533 N⋅m²/C
Q is the total charge Q in the shell = ?
ε₀ is the permittivity of free space = 8.85 x 10⁻¹²
From this equation; Φ = Q/ε₀
Q = Φ * ε₀ = − 533 * 8.85 x 10⁻¹²
Q = −4.7 X 10⁻⁹ C = -4.7nC
Q = q₁ + q₂ + q₃
− 4.7nC = − 14.0 nC + 31.0 nC + q₃
− 4.7nC − 17nC = q₃
− 21.7nC = q₃
Therefore, the charge on the third object is − 21.7nC
Responder:
6.704 m / s
Explicación:
Se dice que el trabajo se realiza cuando la fuerza aplicada a un objeto hace que el objeto se mueva. Primero necesitamos calcular la distancia recorrida por el perro usando la fórmula del trabajo realizado.
Trabajo realizado = Fuerza × distancia
Distancia = Trabajo realizado / Fuerza
Distancia = W / mg
S = 176/8 × 9,81
S = 176 / 78,48
S = 2,24 m
Dada la velocidad inicial u = 3.6km / h
Convertir a m / s
= 3.6km × 1000m / 1h × 3600
= 3600/3600
= 1 m / s
u = 1 m / s
Usando la ecuación de movimiento
v² = u² + 2gS para obtener la velocidad final v:
v² = 1² + 2 (9,81) (2,24)
v² = 1 + 43,9488
v² = 44,9488
v = √44,9488
v = 6,704 m / s
Por tanto, la rapidez final del perro es de 6,704 m / s
Answer:
The distance between the two slits is 40.11 μm.
Explanation:
Given that,
Frequency 
Distance of the screen l = 88.0 cm
Position of the third order y =3.10 cm
We need to calculate the wavelength
Using formula of wavelength
where, c = speed of light
f = frequency
Put the value into the formula
We need to calculate the distance between the two slits
Where, m = number of fringe
d = distance between the two slits
Here, 
Put the value into the formula
Hence, The distance between the two slits is 40.11 μm.
