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Nitella [24]
3 years ago
11

How tall would a tower need to be if the period of a pendulum were 30. seconds

Physics
1 answer:
Virty [35]3 years ago
4 0
We use the following expression

T = 2*pi *sqrt(l/g)

Where T is the period of the pendulum

l is the length of the pendulum

and g the acceleration of gravity

We solve for l

l = [T/2*pi]² *g = [30s/2*pi]²* 9.8 [m/s²] = 223.413 m

The tower would need to be at least 223.413 m high
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