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irinina [24]
2 years ago
6

A hot metal bolt of mass 0.06 kg and specific heat capacity 899 J/kg°C is dropped into a calorimeter containing 0.16 kg water at

20°C. The bolt and water reach a final temperature of 25°C.
What is the initial temperature of the bolt?
Physics
1 answer:
skad [1K]2 years ago
7 0

Answer:

Explanation:

Given

mass of hot metal m_1=0.06\ kg

specific heat c=889\ J/kg-^{\circ}C

mass of water m_2=0.16\ kg

Temperature pf water T_2=20^{\circ}C

Final Temperature T=25^{\circ}C

let T_1 be the temperature of hot metal ball

Heat lost by heat metal bolt is gained by water in calorimeter

Heat lost by hot metal bolt Q_1=m\times c\times \Delta T

Q_1=0.06\times 889\times (T-25)

Heat gained by water Q_2=m_2\times c_w\times \Delta T

Q_2=0.16\times 4184\times (25-20)

Q_1=Q_2

0.06\times 889\times (T-25)=0.16\times 4184\times (25-20)

T_1=25+62.75

T_1=87.75^{\circ}C

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