Question

A hot metal bolt of mass 0.06 kg and specific heat capacity 899 J/kg°C is dropped into a calorimeter containing 0.16 kg water at 20°C. The bolt and water reach a final temperature of 25°C.
What is the initial temperature of the bolt?

Answer 1

Answer:

Explanation:

Given

mass of hot metal $m_1=0.06\ kg$

specific heat $c=889\ J/kg-^{\circ}C$

mass of water $m_2=0.16\ kg$

Temperature pf water $T_2=20^{\circ}C$

Final Temperature $T=25^{\circ}C$

let $T_1$ be the temperature of hot metal ball

Heat lost by heat metal bolt is gained by water in calorimeter

Heat lost by hot metal bolt $Q_1=m\times c\times \Delta T$

$Q_1=0.06\times 889\times (T-25)$

Heat gained by water $Q_2=m_2\times c_w\times \Delta T$

$Q_2=0.16\times 4184\times (25-20)$

$Q_1=Q_2$

$0.06\times 889\times (T-25)=0.16\times 4184\times (25-20)$

$T_1=25+62.75$

$T_1=87.75^{\circ}C$