1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
BlackZzzverrR [31]
4 years ago
8

How do both plants and animals fight pathogens. A.both have a protective outer layer B.both have an antigen-antibody response C.

Both have a lymphatic system D. Both produce lymphocytes????? Plzz help
Chemistry
2 answers:
katrin [286]4 years ago
7 0

The answer is A. both have a protective outer layer

ira [324]4 years ago
3 0
<span>Both plants and animals fight pathogens is because both have an ant. </span><span>The answer is B. 

P</span>athogens is <span>a bacterium, virus, or other microorganism that can cause disease.

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.
</span>
You might be interested in
N2(g) + 2H(g) -&gt; N2 H4(g) What are the volumes of N2 gas and H2 gas required to form 28.5 grams of N2 H4 at 30'C and 1.50 atm
FromTheMoon [43]

Answer:

Volume of N₂ = 14.76 L

Volume of H₂ = 29.52 L

Explanation:

Given data:

Mass of N₂H₄ formed = 28.5 g

Pressure = 1.50 atm

Temperature = 30°C (30+273 = 303 k)

Volume of N₂ and H₂ needed = ?

Solution:

Chemical equation:

N₂ + 2H₂  →  N₂H₄

Number of moles of N₂H₄ formed = mass/ molar mass

Number of moles of N₂H₄ formed = 28.5 g/ 32 g/mol

Number of moles of N₂H₄ formed = 0.89 mol

Now we will compare the moles of N₂H₄ with N₂ and H₂ form balance chemical equation.

                N₂H₄                :                 N₂

                   1                     :                   1

                  0.89               :               0.89

                N₂H₄                :                 H₂

                   1                    :                  2

                 0.89               :                2×0.89 = 1.78 mol

Volume of H₂:

PV = nRT

1.50 atm × V = 1.78 mol × 0.0821 atm.L/mol.K × 303 K

V = 44.28atm.L /1.50 atm

V = 29.52 L

Volume of N₂:

PV = nRT

1.50 atm × V = 0.89 mol × 0.0821 atm.L/mol.K × 303 K

V = 22.14 atm.L /1.50 atm

V = 14.76 L

6 0
3 years ago
Interpretacao gerais das praticas <br>sobre densidade de amostra solido e liquido<br>​
Savatey [412]

Answer:

O sólido tem densidade mais alta em comparação ao líquido.

Explicação:

A densidade da amostra sólida é maior do que a densidade do líquido porque há pouco espaço entre as partículas do sólido. A densidade tem relação inversa com o volume de uma substância, se uma substância ocupa mais espaço então sua densidade é menor, enquanto se a substância ocupa menos espaço então tem maior densidade. As substâncias sólidas ocupam menos espaço em comparação com as substâncias líquidas, então podemos dizer que a densidade do sólido é maior do que as substâncias líquidas.

6 0
3 years ago
Calculate the freezing point of a solution that contains 1.75 mol of nacl dissolved in 1.00 kg of water. be sure to enter the ne
matrenka [14]
In order to calculate the new freezing point, we must first find the depression. This is given by:

ΔT = Kf * b * i

where Kf is the cryscopic constant for the solvent, b is the molarity of the solution in moles per kilogram and i is the van't Hoff factor, which tells us how many ions will be released when a substance is dissolved. 

Kf = 1.853, b = 1.5, i = 2 (Na⁺ and Cl⁻)

ΔT = 5.5 °C

The new freezing point will be 0 + 5.5
5.5 °C
3 0
3 years ago
Predict the spontaneity of a reaction (and the temperature dependence of the spontaneity) for each possible combination of signs
Akimi4 [234]

Answer and Explanation:

At constant pressure and constant temperature, the Gibbs free energy of a process is given by the following equation:

ΔG= ΔH - T ΔS

The process is spontaneous when ΔG<0. For this, there are four alternatives depending on the signs of ΔH and ΔS and the temperature (T):

1) ΔH negative, ΔS positive ⇒ b)The reaction will be spontaneous at all temperatures.

ΔG= (-H) - T (+S)   ⇒ ΔG<0 always

2) ΔH positive, ΔS negative ⇒ c)The reaction will be nonspontaneous at all temperatures.

ΔG= (+H) - T (-S)   ⇒ ΔG>0 always

3) ΔH negative, ΔS negative ⇒ d)The reaction will be spontaneous at low temperature, but nonspontaneous at high temperature.

ΔG= (-H) - T (-S)  ⇒ ΔG<0 if TΔS is lower than ΔH, because is the positive term

4)ΔH positive, ΔS positive ⇒ a)The reaction will be nonspontaneous at low temperature, but spontaneous at high temperature.

ΔG= (+H) - T (+S) ⇒ ΔG<0 if TΔS higher than ΔH because is the negative term

8 0
3 years ago
How many moles of gas would occupy 22.4 L at 273K in one arm?
andrew-mc [135]

Answer:

1 mol

Explanation:

Using the general gas law equation as follows:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

According to the provided information in the question;

V = 22.4L

T = 273K

P = 1 atm

R = 0.0821 Latm/molK

n = ?

Using PV = nRT

n = PV/RT

n = (1 × 22.4) ÷ (0.0821 × 273)

n = 22.4 ÷ 22.4

n = 1mol

4 0
3 years ago
Other questions:
  • The formula C2H4 can be described as
    9·2 answers
  • Write down the common name of the elements shown in the given table . If<br>F<br>cl<br>Br<br>I​
    12·2 answers
  • Read the given chemical reaction.
    11·1 answer
  • An important reaction sequence in the industrial production of nitric acid is the following:
    12·1 answer
  • Question 5
    11·1 answer
  • State two causes of cracked and sore nipples during breastfeeding
    10·1 answer
  • Example: Sugar (C12H22O11) - Add up the masses of each element. (Look at your periodic table for the masses.)
    8·1 answer
  • The phase transition of dry ice (frozen carbon dioxide ) to gas is an example of
    9·1 answer
  • Give some tips on how to take care of your microscope.
    5·2 answers
  • PLEASE HELP ITS RLLY HARD
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!