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Paladinen [302]
3 years ago
12

Potassium chlorate is a mean little chemical. It likes to decompose rather violently, and when it does, it decomposes into two d

ifferent products--potasssium chloride and a gas. What is this gas produced in the reaction?
Chemistry
1 answer:
WARRIOR [948]3 years ago
6 0

Answer:

Oxygen gas

Explanation:

Potassium chlorate KClO3 decomposes thermally to form potassium chloride KCl and oxygen gas is given off. This is in the presence of a catalyst, manganese iv oxide.

Hence, what is being said in essence is that when potassium chloride is heated in the presence of manganese iv oxide catalyst, oxygen is given off as the gaseous product with the formation of potassium chloride.

The chemical equation for the reaction is :

2KClO3 ——-> 2KCl + 3O2

This procedure is one of most important ways through which oxygen can be produced in the laboratory and can be used as a source of oxygen is industrial processes if on a large scale

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If 60 grams of a liquid takes up 120ml how dense is the liquid
Black_prince [1.1K]

Answer:

<h2>Density = 0.5 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

<h3>Density =  \frac{mass}{volume}</h3>

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mass = 60 g

volume = 120 mL

Substitute the values into the above formula and solve

That's

<h3>Density =  \frac{60}{120}  \\  =  \frac{1}{2}</h3>

We have the final answer as

<h3>Density = 0.5 g/mL</h3>

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4 0
3 years ago
Calculate the volume in liters of a potassium iodide solution that contains of potassium iodide . Be sure your answer has the co
Anna11 [10]

Answer:

23.8 L

Explanation:

There is some info missing. I think this is the original question.

<em>Calculate the volume in liters of a 0.0380M potassium iodide solution that contains 150 g of potassium iodide. Be sure your answer has the correct number of significant digits.</em>

<em />

The molar mass of potassium iodide is 166.00 g/mol. The moles corresponding to 150 grams are:

150 g × (1 mol/166.00 g) = 0.904 mol

0.904 moles of potassium iodide are contained in an unknown volume of a 0.0380 mol/L potassium iodide solution. The volume is:

0.904 mol × (1 L/0.0380 mol) = 23.8 L

6 0
3 years ago
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