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storchak [24]
3 years ago
9

What is the concentration of a solution in which 10.0 g of AgNO, is dissolved in 450 mL of solution?

Chemistry
1 answer:
Rufina [12.5K]3 years ago
4 0

Answer:

M=0.15

Explanation:

138 g AgNO -> 1 mol AgNO

10 g AgNO   -> x

x= (10 g AgNO * 1 mol AgNO)/138 g        x=0.07 mol AgNO

450 mL=0.45 L

M= mol solute/L solution

M= 0.07 mol AgNO/0.45L

M=0.15

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What is the percent by mass of Fluorine in Nitrogen triflouride NF3?
Kipish [7]

Answer:

The answer to your question is 80.3%

Explanation:

Data

Percent by mass of F

molecules NF₃

Process

1.- Calculate the molar mass of nitrogen trifluoride

molar mass = (1 x 14) + (19 x 3)

                    = 14 + 57

                    = 71 g

2.- Use proportions and cross multiplications to find the percent by mass of F. The molar mass of NF₃ is equal to 100%.

                       71 g of NF₃ ------------------ 100%

                       57 g of F   ------------------- x

                            x = (57 x 100)/71

                            x = 5700 / 71

                            x = 80.3%

3.- Conclusion

Fluorine is 80.3% by mass of the molecule NF₃

           

3 0
3 years ago
A container holds 15.0 g of phosphorous gas at a pressure of 2.0 atm and a temperature of 20.0 Celsius. What is the density of t
erik [133]
<span>Density is a value for mass, such as kg, divided by a value for volume, such as m3. Density is a physical property of a substance that represents the mass of that substance per unit volume. We calculate as follows:

PV = nRT
PV = mRT/ Molar mass
m/V = P(molar mass)/RT
Density = P(molar mass)/RT 
Density = 2.0 ( 30.97 ) / 0.08206 ( 20 + 273.15) = 2.57 g/L <----First option</span>
5 0
3 years ago
Read 2 more answers
The reaction NA3PO4(aq) + 3 AgNO3(aq) → Ag3PO4() + 3NaNO 3( aq) is best classified as a(n)?
Natasha2012 [34]

Answer:

Double replacement reaction.

Explanation:

The Na and Ag atoms both (double) trade places (replacement) with each other.  

8 0
2 years ago
Using the thermodynamic information in the ALEKS Data tab, calculate the boiling point of titanium tetrachloride . Round your an
ddd [48]

Answer:

The boiling point is 308.27 K (35.27°C)

Explanation:

The chemical reaction for the boiling of titanium tetrachloride is shown below:

TiCl_{4(l)} ⇒ TiCl_{4(g)}

ΔH°_{f} (TiCl_{4(l)}) = -804.2 kJ/mol

ΔH°_{f} (TiCl_{4(g)}) = -763.2 kJ/mol

Therefore,

ΔH°_{f} = ΔH°_{f} (TiCl_{4(g)}) - ΔH°_{f} (TiCl_{4(l)}) = -763.2 - (-804.2) = 41 kJ/mol = 41000 J/mol

Similarly,

s°(TiCl_{4(l)}) = 221.9 J/(mol*K)

s°(TiCl_{4(g)}) = 354.9 J/(mol*K)

Therefore,

s° = s° (TiCl_{4(g)}) - s°(TiCl_{4(l)}) = 354.9 - 221.9 = 133 J/(mol*K)

Thus, T = ΔH°_{f} /s° = [41000 J/mol]/[133 J/(mol*K)] = 308. 27 K or 35.27°C

Therefore, the boiling point of titanium tetrachloride is 308.27 K or 35.27°C.

5 0
3 years ago
Which element(s) are not balanced in this equation?
poizon [28]
The correct response is A. Only the Fe is unbalanced.
6 0
3 years ago
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