1) 0.89% m/v = 0.89 grams of NaCl / 100 ml of solution
=> 8.9 grams of NaCl in 1000 ml of solution = 8.9 grams of NaCl in 1 liter of solution
2) Molarity = M = number of moles of solute / liters of solution
=> calculate the number of moles of 8.9 grams of NaCl
3) molar mass of NaCl = 23.0 g /mol + 35.5 g/mol = 58.5 g / mol
4) number of moles of NaCl = mass / molar mass = 8.9 g / 58.5 g / mol = 0.152 mol
5) M = 0.152 mol NaCl / 1 liter solution = 0.152 M
Answer: 0.152 M
Answer:
Fe(OH)2
Explanation:
Iron hydroxides are chemical compounds that appear as precipitates after alkalizing solutions containing iron salts, both in their valence or degree of oxidation (III) and (II).
Hydroxide, in both cases, is a gelatinous colloid of difficult filtration that can be considered a hydrated oxide, iron (II) hydroxide is whitish in color and requires more alkalinization, above 7.
