Answer:
- <u>609g </u>
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Explanation:
The translated question is:
<em>What maximum amount of grams of potassium nitrate (V) can be dissolved in 300g of water at 90 °C</em>
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<h2>Solution</h2><em></em>
To answer the question you need to consultate the solubiity information for potassium nitrate (V), KNO₃.
The attached table contains the solutibility table for KNO₃ at different temperatures.
At 90ºC it is 203g / 100g water.
Then, to calculate the <em>maximum amount of grams of potassium nitrate (V) that can be dissolved in 300g of water at 90 °C</em>, just multiply by the amount of water:
- 203g / 100g water × 300 g water = 609g ← answer
