Fill in the coefficients that will balance the following reaction:
1 answer:
These are 9 questions and 9 aswers. 1) Fill in the coefficients that will balance the following reaction: <span>A₀ Hg(CO₃)₂ + A₁ AgCl → A₂HgCl₄ + A₃Ag₂CO₃ Answer: Balance in Hg ⇒ A₀ = A2 Balance in Ag ⇒ A₁ = 2A₃ Balance is CO₃ ⇒ 2A₀ = A₃ Balance is Cl ⇒A₁ = 4Cl₄ ⇒ System of equations: </span><span><span>A₀ = A2 A₁ = 2A₃ 2A₀ = A₃ A₁ = 4A₂</span> Start by stating A₂ = 1 ⇒ A₁ = 4 A₃ = 4/2 = 2 A₀ = 2/2 = 1 Therefore, the resulting balanced reaction is: </span><span>Hg(CO₃)₂ + 4 AgCl → HgCl₄ + 2 Ag₂CO₃ <-------- answer
2) Fill in the coefficients that will balance the following reaction:a₀ Fe(HCO₃)₃ + a₁CaO → a₂Fe₂O₃ + a₃Ca(HCO₃)₂ Answer: Balance in Fe: a₀ = 2a₂ Balance in H: 3a₀ = 2a₃ Balance in C: 3a₀ = 2a₃ Balance in O: 9a₀ = 3a₂ + 6a₃ Balance in Ca: a₁ = a₃ Start with a₃ = 3 ⇒ a₀ = 2 a₁ = 3 a₂ = 1 a₃ = 3 Therefore, the resulting balanced equation is: </span><span>2 Fe(HCO₃)₃ + 3CaO → Fe₂O₃ + 3 Ca(HCO₃)₂ <----------- answer 3) Fill in the coefficients that will balance the following reaction:
a₀C₃H₇OH + a₁O₂ → a₂CO₂ + a₃H₂O Answer : Balance in C: 3a₀ = a₂ Balance in H: 8a₀ = 2a₃ Balance in O: a₀ + 2a₁ = 2a₂ + a₃ Start with a₃ = 4 ⇒ a₀ = 1 a₂ = 3 1 + 2 a₁ = 2×3 + 4 ⇒ a₁ = 4,5 to make alll the coefficients integers multiply by 2: a₃ = 8 a₀ = 2 a₂ = 6 a₁ = 9 Therefore, the resulting balanced chemical equation is: </span> <span>
2C₃H₇OH + 9O₂ → 6CO₂ + 8H₂O 4) Fill in the coefficients that will balance the following reaction:
a₀SnSO₄ + a₁KBr → a₂SnBr₂ + a₃K₂SO₄ Answer: Balance in Sn: a₀ = a₂ Balance in SO₄: a₀ = a₃ Balance in K: a₁ = 2a₃ Balance in Br: a₁ = 2a₂ Start with a₃ = 1 ⇒ a₀ = 1 a₁ = 2 a₂ = 1 Therefore, the resulting balance equation is: </span> <span>
SnSO₄ + 2KBr → SnBr₂ + K₂SO₄ <------------ answer
5) Fill in the coefficients that will balance the following reaction:
a₀NH4Cl + a₁Ag3PO4 → a₂AgCl + a₃(NH4)3PO4 a₂ = 3 a₁ = 1 a₀ = 3 a₃ = 1⇒ </span><span>3 NH₄Cl + Ag₃PO₄ → 3 AgCl + (NH₄)₃PO₄ <-------- answer
6) Fill in the coefficients that will balance the following reaction:
a₀Cr₂(SO₄)₃ + a₁AgNO₃ → a₂Cr(NO₃)₃ + a₃Ag₂SO₄ Answer: a₀ = 1 a₁ = 6 a₂ = 2 a₃ = 3 Resulting balanced equation: </span><span>Cr₂(SO₄)₃ + 6AgNO₃ → 2Cr(NO₃)₃ + 3Ag₂SO₄ 7) Fill in the coefficients that will balance the following reaction:
a₀NaC₂H₃O₂ + a₁Fe₂O₃ → a₂Fe(C₂H₃O₂)₃ + a₃Na₂O Answer : Balance in Na: a₀ = 2a₃ Balance in </span><span>C₂H₃O₂ : a₀ = 3a₂ Balance in Fe: 2a₁ = a₂ Balance in O: 3a₁ = a₃ Start with a₃ = 3 ⇒ a₁ = 1 a₂ = 2 a₀ = 6 ⇒ </span><span>6NaC₂H₃O₂ + Fe₂O₃ → 2Fe(C₂H₃O₂)₃ + 3Na₂O ← answer 8) Fill in the coefficients that will balance the following reaction:
a₀CH₄ + a₁O₂ → a₂CO₂ + a₃H₂O a₀ = 1 a₁ = 2 a₂ = 1 a₃ = 2⇒ </span><span>CH₄ + 2O₂ → CO₂ + 2H₂O ← answer 9) Fill in the coefficients that will balance the following reaction:
a₀NaCl + a₁FeO → a₂Na₂O + a₃FeCl₂ Answer: a₀ = 2 a₁ = 1 a₂ = 1 a₃ = 1 </span>2NaCl + FeO → Na₂O + FeCl₂ ← answer
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Here we apply the Clausius-Clapeyron equation: ln(P₁/P₂) = ΔH/R x (1/T₂ - 1/T₁) The normal vapor pressure is 4.24 kPa (P₁) The boiling point at this pressure is 293 K (P₂) The heat of vaporization is 39.9 kJ/mol (ΔH) We need to find the vapor pressure (P₂) at the given temperature 355.3 K (T₂) ln(4.24/P₂) = 39.9/0.008314 x (1/355.3 - 1/293) P₂ = 101.2 kPa
Answer:
See explanation.
Explanation:
Hello!
In this case, when having the cationic and anionic species with the specified charges, in order to abide by the net charge rule, we need to exchange the charges in the form of subscripts and without the sign, just as shown below:
Thus, for all the given combinations, we obtain:
- Y⁻
- Y²⁻
- Y³⁻
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Calculating speed or atoms and molecules or planets! Hope i helped plz mark as brainlist!
Answer:
I’m not a expert on it, but I think B or D
Explanation:
Yep. And you'll always get equations with units that don't match