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Kryger [21]
3 years ago
6

State the number of electrons that must be lost by atoms of

Chemistry
1 answer:
Snowcat [4.5K]3 years ago
4 0

<u>The number of electrons that must be lost by atoms of each given to achieve a stable electron configuration are as follows: </u>

  • Li has to lose 1 electron
  • Ca has to lose 2 electrons
  • Ga has to lose 13 electrons
  • Cs has to lose 1 electron
  • Ba has to lose 2 electrons.

<u>Explanation: </u>

It is known that the elements in the last group or we can stay the noble gases have the most stable electron configuration. So if any other element has to attain stable electron configuration, either they have to loose electrons to attain the electronic configuration similar to its closest noble gas element or they have to attain extra electron to reach the electronic configuration of its nearest noble gas element.

In this case, the question is stated to determine the number of electrons lost by the atoms to reach its stable electron configuration. Thus, the outermost shell electrons or the valence state electrons can be lost by the element to attain the electronic configuration of its nearest noble gas element.

So, the elements given in the question need to lose the electrons such that the electronic configuration of the element after losing of electrons will be equal to the electronic configuration of noble elements. This attainment of noble gas configuration by the elements will be achieving the stable electron configuration.

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Lithium (Li) and oxygen (O) are both in period 2. They both have _____.
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They both have two electron shells

<h3>Further explanation</h3>

The period 2 element lies in the second row of the periodic system.

Consists of the elements: lithium, beryllium, boron, carbon, nitrogen, oxygen, fluorine, and neon

  • Lithium (Li)

atomic number : 3

electron configuration : [He] 2s¹

atomic number = number of proton=number of electron(in neutral atom)

So Li have 3 protons and 3 electrons

Because it fills the 2s orbital it has 2 shells

  • Oxygen (O)

atomic number : 8

electron configuration :  [He] 2s²2p⁴

So O have 8 protons and 8 electrons

Because it fills the 2s and 2p orbital it has 2 shells

So Lithium (Li) and Oxygen (O) are both have two electron shells

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3 years ago
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The chemical equation is Mg(s) + O2(g) → MgO(s)
vredina [299]

Answer:

The magnesium will burn until consumed entirely. There is much more oxygen available in the atmosphere than needed to consume the magnesium. Thus the magnesium is the limiting reactant because it determines the amount of product formed.

Explanation:

Mg produces less amount of MgO than O2; therefore Mg is the limiting reagent. O2 produces more amount of MgO than Mg; therefore O2 is the excess reagent.

4 0
3 years ago
If 20.0 mL of a 0.0800 M HNO3, 35.0 mL of a 0.0800 M KSCN, and 40.0 mL of a 0.0800 M Fe(NO3)3 are combined, what is the initial
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0.0295M

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As you can see, in the mixture you have KSCN and other compounds. The KSCN in solution is dissolved in K⁺ ions and SCN⁻ ions. That means initial concentration of SCN⁻ ions is the same of KSCN, 0.0800M.

You are adding 35.0mL of this solution and the total volume of the mixture is 20.0mL + 35.0mL + 40.0mL = 95.0mL.

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<h3>0.0295M </h3>

4 0
3 years ago
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