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Kryger [21]
3 years ago
6

State the number of electrons that must be lost by atoms of

Chemistry
1 answer:
Snowcat [4.5K]3 years ago
4 0

<u>The number of electrons that must be lost by atoms of each given to achieve a stable electron configuration are as follows: </u>

  • Li has to lose 1 electron
  • Ca has to lose 2 electrons
  • Ga has to lose 13 electrons
  • Cs has to lose 1 electron
  • Ba has to lose 2 electrons.

<u>Explanation: </u>

It is known that the elements in the last group or we can stay the noble gases have the most stable electron configuration. So if any other element has to attain stable electron configuration, either they have to loose electrons to attain the electronic configuration similar to its closest noble gas element or they have to attain extra electron to reach the electronic configuration of its nearest noble gas element.

In this case, the question is stated to determine the number of electrons lost by the atoms to reach its stable electron configuration. Thus, the outermost shell electrons or the valence state electrons can be lost by the element to attain the electronic configuration of its nearest noble gas element.

So, the elements given in the question need to lose the electrons such that the electronic configuration of the element after losing of electrons will be equal to the electronic configuration of noble elements. This attainment of noble gas configuration by the elements will be achieving the stable electron configuration.

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When 3.0 grams of H2 is reacted with excess C at constant pressure, the reaction forms CH4 and releases 53.3 kJ of heat. C(s) +
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Answer:

THE ENTHALPY OF REACTION IN KJ/MOL OF CH4 IS 7.07 KJ/MOL.

Explanation:

Mass of H2 = 3 g

Molar mass of H2 = 2 g/mol

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Equation of the reaction:

C(s) + 2H2(g) -------> CH4(g)

First:

Calculate the number of moles of H2 that was used:

Number of moles = mass / molar mass

Number of moles = 3g / 2g

Number of moles = 1.5 moles

So therefore, when 53.3 kJ of heat was released from the reaction, 1.5 moles of hydrogen was used.

From the equation of the reaction, one mole of carbon reacts with two moles of hydrogen to form one mole of methane.

For 3 g of hydrogen, 1.5 mole of hydrogen is involved.

It means:

1.5 moles of hydrogen reacts with 0.75 moles of carbon and produces 0.75 moles of methane. This is so because the reaction occurs in 1: 2: 1 in respect to carbon, hydrogen and methane respectively.

So we can say that the production of 0.75 mole of methane will evolve 53.3 kJ of heat.

0.75 mole of methane releases 53.3 kJ of heat.

1 mole of methane will release ( 53.3 kJ * 1 / 0.75 )

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In conclusion, the enthalpy of the reaction in kJ/ mole of CH4 is 71.07 kJ/mol.

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