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Kryger [21]
3 years ago
6

State the number of electrons that must be lost by atoms of

Chemistry
1 answer:
Snowcat [4.5K]3 years ago
4 0

<u>The number of electrons that must be lost by atoms of each given to achieve a stable electron configuration are as follows: </u>

  • Li has to lose 1 electron
  • Ca has to lose 2 electrons
  • Ga has to lose 13 electrons
  • Cs has to lose 1 electron
  • Ba has to lose 2 electrons.

<u>Explanation: </u>

It is known that the elements in the last group or we can stay the noble gases have the most stable electron configuration. So if any other element has to attain stable electron configuration, either they have to loose electrons to attain the electronic configuration similar to its closest noble gas element or they have to attain extra electron to reach the electronic configuration of its nearest noble gas element.

In this case, the question is stated to determine the number of electrons lost by the atoms to reach its stable electron configuration. Thus, the outermost shell electrons or the valence state electrons can be lost by the element to attain the electronic configuration of its nearest noble gas element.

So, the elements given in the question need to lose the electrons such that the electronic configuration of the element after losing of electrons will be equal to the electronic configuration of noble elements. This attainment of noble gas configuration by the elements will be achieving the stable electron configuration.

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Enter your answer in the provided box. When mixed, solutions of barium chloride, BaCl2, and potassium chromate, K2CrO4, form a y
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Answer:

35.42g

Explanation:

Step 1:

The balanced equation for the reaction

BaCl2(aq) + K2CrO4(aq) → BaCrO4(s) + 2KCl(aq)

Step 2:

Determination of the limiting reactant.

It is important to determine which of the reactant is limiting the reaction as the limiting reactant is used to determine the maximum yield of the reaction. The limiting reactant can be determined as follow:

From the balanced equation above,

1 mole of BaCl2 reacted with 1 mole of K2CrO4.

Therefore, 0.7 mole of BaCl2 will also react with 0.7 mol of K2CrO4.

From the above illustration, we can see that it requires a higher amount of K2CrO4 to react with 0.7 mol of BaCl2. This simply means that K2CrO4 is the limiting reactant.

Step 3:

Determination of the number of mole of BaCrO4 produced from the reaction.

The limiting reactant is used in this case.

From the balanced equation above,

1 mole of K2CrO4 produced 1 mole of BaCrO4.

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Step 4:

Converting 0.14 mole of BaCrO4 to grams.

This is illustrated below:

Molar Mass of BaCrO4 = 137 + 52 + (16x4) = 137 + 52 + 64 = 253g/mol

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Mass of BaCrO4 =?

Mass = number of mole x molar Mass

Mass of BaCrO4 = 0.14 x 253

Mass of BaCrO4 = 35.42g

Therefore, 35.42g of BaCrO4 is produced from the reaction.

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