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2 years ago

What volume is occupied by 22.1 g of O2 at 52°C and a pressure of 1.63 atm?

1 answer:

Nutka1998 [239]2 years ago

3 0

U can use PV=nRT
where n=mass in grams/ molar mass
temp will be converted into kelvin by adding 273k
the value of R = 0.0821
try it by yourself :)

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Identify the reactants and products in the following chemical equation: Zn +2HCl --> ZnCl2 + H2 *

Ad libitum [116K]

Answer:

Explanation:

zinc and hydrochloric acid reacts to form zinc chloride and hydrogen.

hope it helps. :)

7 0

2 years ago

All of the following are indicators of chemical change except…

Oduvanchick [21]

D. All of the above are indicators of chemical change

7 0

3 years ago

Metals posses varying reduction potentials. Iron can reduce Cu+2 (aq) to copper metal. Silver can reduce Au+ (aq) to gold metal.

natta225 [31]

Answer: The true statement is iron can reduce $Au^+(aq)$ to gold metal

Explanation:

Single displacement reaction is defined as the reaction in which more reactive element displaces a less reactive element from its chemical reaction.

The reactivity of metal is determined by a series known as reactivity series. The metals lying above in the series are more reactive than the metals which lie below in the series.

$A+BC\rightarrow AC+B$

Metal A is more reactive than metal B.

We are given:

Iron can reduce copper, silver can reduce gold, sodium can reduce iron and copper can reduce silver metal.

The increasing order of reactivity thus follows:

$Au$

where, sodium is most reactive and gold is least reactive

For the given options:

Option 1: Copper cannot easily reduce sodium ion to sodium metal because it is less reactive.

$Cu(s)+Na^+(aq.)\rightarrow \text{ No reaction}$

Option 2: Iron cant easily reduce gold ion to gold metal because it is more reactive.

$Fe(s)+3Au^+(aq.)\rightarrow Fe^{3+}(aq.)+3Au(s)$

Option 3: Silver cannot easily reduce iron ion to iron metal because it is less reactive.

$Ag(s)+Fe^{3+}(aq.)\rightarrow \text{ No reaction}$

Hence, the true statement is iron can reduce $Au^+(aq)$ to gold metal

7 0

2 years ago

How do you determine the volume of a regular object if you don't know the density?

Ann [662]

Answer:

mol times or devided by molar volume

4 0

2 years ago

The ion p3− has _____ protons and _____ electrons. enter your answers as integers separated by a comma.'

katrin2010 [14]

The symbol $P$ is for phosphorus having atomic number 15. That means it has $15 protons and 15 electrons$ in its neutral state.

The given symbol $P^{3-}$ has a -3 charge that means it has gained 3 electrons so, the number of electrons in the $P^{3-}$ is: $15+3 = 18$ . The number of protons will remain same that is the number of protons = 15.

So, the ion $P^{3-}$ has $15 protons and 18 electrons$ that gives $15-18=-3$ charge on the $P^{3-}$ ion.

So, the answer is $15 , 18$ .

7 0

2 years ago