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3 years ago

How many oxygen atoms are there in the following compound: 2HNO3 3 5 6 12

Chemistry

2 answers:

Fudgin [204]3 years ago

7 0

Answer:

Explanation:

There is 2 of the coumpond, in one compound, there are 3 oxygens. But when there are two, it is 6.

Ahat [919]3 years ago

3 0

Answer:

The answer is there are 3 oxygen atoms.

Explanation:

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9. A graduated cylinder is filled with water to a level of 40.0 mL. When a piece of copper is lowered into the cylinder, the wat

horsena [70]

Answer:

Mass = 208.26 g

Explanation:

Given data:

Volume of water = 40.0 mL

Volume of water + copper = 63.4 mL

Volume of copper = ?

Density of copper = 8.9 g/cm³

Mass of copper = ?

Solution:

Volume of copper:

Volume of copper = (Volume of water + copper ) - Volume of water

Volume of copper = 63.4 mL - 40.0 mL

Volume of copper = 23.4 mL

Mass of copper:

density = mass/volume

8.9 g/cm³ = mass/23.4 mL

cm³ = mL

Mass = 8.9 g/mL × 23.4 mL

Mass = 208.26 g

5 0

3 years ago

What Are Sound Waves? Please HELP!

Elza [17]

Answer:Sound waves are longitudinal waves that travel through a medium like air or water. When we think about sound, we often think about how loud it is (amplitude, or intensity) and its pitch (frequency).

Explanation:

6 0

3 years ago

The radiator in a car is filled with a solution of 60% antifreeze and 40% water. The manufacturer of the antifreeze suggests tha

lakkis [162]

Answer:

0.6 Liters of coolant should be drained and 0.6 Liter of water should be added.

Explanation:

Volume of the radiator = 3.6 L

Percentage of antifreeze = 60%

Total volume of anti freeze in radiator = 60% of 3.6 L :

$\frac{60}{100}\times 3.6 = 2.16 L$

Percentage of water= 40%

Given,optimal cooling of the engine is obtained with only 50% antifreeze.

So, now we want to reduce the percentage of antifreeze from 60% to 50 %

Volume of coolant removed = x

Volume of water added = x

Volume of anti freeze removed = 60% of(x) = 0.6x

Volume of antifreeze left in radiator =50% of 3.6 L = $\frac{50}{100}\times 3.6=1.8 L$

1.8 Liter is the desired volume of the antifreeze.

Total volume - Removed volume = desired volume

2.16 L - 60% of( x) = 1.8 L

$2.16 L-0.6x=1.8 L$

$x=\frac{2.16 l- 1.8 L}{0.6}=0.6 L$

0.6 Liters of coolant should be drained and 0.6 Liter of water should be added.

4 0

4 years ago

At this point Ron is slightly confused, this isn’t surprising. However, Hermione is doing rather well with them. This also isn’t

Zigmanuir [339]

Answer:

$\boxed{\text{0.780 atm}}$

Explanation:

Hermione is pretty smart. She realizes that, according to Dalton's Law of Partial Pressures, each gas exerts its pressure independently of the others, as if the others weren't even there.

She shows Ron how to use the Ideal Gas Law to solve the problem.

pV = nRT

She collects the data:

V = 1.00 L; n = 0.0319 mol; T = 25.0 °C

She reminds him to convert the temperature to kelvins

T = (25.0 +273.15) K = 298.15 K

Then she shows him how to do the calculation.

$p \times \text{1.00 L} = \text{0.0319 mol} \times \text{L}\cdot\text{atm}\cdot\text{0.082 06 K}^{-1}\text{mol}^{-1} \times \text{298.15 K}\\\\1.00p = \text{0.7805 atm}\\\\p = \textbf{0.780 atm}\\\\\text{The partial pressure of the nitrogen is } \boxed{\textbf{0.780 atm}}$

Isn't she smart?

4 0

3 years ago

The active ingredient in aspirin is acetylsalicylic acid (MW = 180.2 g/mol). An aspirin tablet was dissolved in

Mashcka [7]

Answer:

1214 mg

Explanation:

Data given

Volume of NaOH solution (V) = 14.85 mL

Molarity of NaOH solution (M) = 0.100 M NaOH.

Amount of acetylsalicylic acid = ?

Molecular weight = 180.2 g/mol

Solution:

It is a acid base titration

As equal amount of NaOH will neutralize equal amount of acetylsalicylic acid.

First find the moles of NaOH

As we know

M = moles of solute / 1 L x volume of solution

Rearrange and modify the above equation

moles of NaOH = M of NaOH x 1 L / volume of NaOH solution

Put values in above equation

moles of NaOH = 0.100 M x 1 L / 14.85 mL

moles of NaOH = 0.0067 moles

Now find to find the weight of acetylsalicylic acid

equal amount of NaOH will neutralize equal amount of acetylsalicylic acid.

moles of acetylsalicylic acid = moles of NaOH.......... (1)

As we know

no. of moles = mass in g / molar mass

So,

The modified form of equation 1 will be

mass in g / molar mass (acetylsalicylic acid) = moles of NaOH

Put values in above equation

mass in g / 180.2 g/mol = 0.0067 moles

Rearrange the above equation

mass of acetylsalicylic acid = 0.0067 moles x 180.2 g/mol

mass of acetylsalicylic acid = 1.214 g

Convert the grams to milligrams

1 g = 1000 milligram

So,

1.214 g = 1214 mg

5 0

4 years ago