Answer:
They have the same density
Explanation:
One very accurate statement about the properties of the the water in each of the given cylinder is that their densities are the same.
Density is the mass per unit volume of a compound or substance.
Density is an intensive property of all matter. It does not depend on the amount of matter present.
So, the water density in the two cylinder will both have the same value. This is irrespective of the volume of water in the cylinder.
The given compound 1-bromo-1-chlorobutane is an optically active compound .
Because this compound does not have plane of symmetry (POS) and center of symmetry (COS) i.e. does not have di-symmetry . And also forms non superimposable mirror image . the compound is optically active .
It has chiral center.
Here , the chiral carbon is bonded to 4 distinct groups such as : chlorine , bromine , hydrogen and propyl .
<h3>What is di-symmetry?</h3>
Di-symmetry is that which have no center of symmetry and plane of symmetry and alternate axis of symmetry .
<h3>Chiral center :</h3>
Have Sp3 hybridized center (4sigma bond ) .
4 distinct group is attached to the chiral atom. form non -superimposable mirror image .
<h3>What is optical isomerism ?</h3>
Same molecular formula and same structural formula . also have same physical and chemical properties .
They differ in their behavior towards plane polarized light (ppl) .
Learn more about chiral center here:
brainly.com/question/9522537
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Answer:
a. 0.5 mol
b. 1.5 mol
c. 0.67
Explanation:
Fe3+ + SCN- -----> [FeSCN]2+
a. The ratio of the product to Fe3+ is 1:1. Meaning that if 0.5 mol of product was produced up then 0.5 mol of Fe3+ was used. Leaving 0.5 mol remaining at equilibrium
b. The ratio of the product to SCN= is 1:1. Meaning that if 0.5 mol of product was produced up then 0.5 mol of SCN- was used. Leaving 1.5 mol remaining at equilibrium
c. KC = 0.5/(0.5*1.5) = 0.67
Hydrogen is composed of H atom and oxygen is composed of O atom. For water, it is composed by both H and O atom. If you burn hydrogen in oxygen, you can get water. And if you electrolysis water, you can get hydrogen and oxygen.
K= [Ar] 4s^1
Pb= [Xe] 6s^2 5d^10 6p^2
Sc= [Ar] 4s^2 3d^1
Ra= [Rn] 7s^2
O= [He] 2s^2 2p^4
Ag= [Kr] 5s^2 4d^9
Ru= [Kr] 5s^1
Ce= [Xe] 6s^2 5d^1 4f^1
I= [Kr] 5s^2 4d^10 5p^5
F= [He] 2s^2 2p^5
