The statement "<span>A hit-and-run incident is one of the more common cases for paint evidence." is true. This is shown by a</span><span> spot close to the point of impact, but in a place that has not been damaged.</span>
Answer:
a. The speed is 2.39 m/s
b. The acceleration of the block is 10.2
Explanation:
First, we have to do the energy balance where we consider two states, the first where the spring remains still and the second when it is stretched 0.400m:
Δx=
W_{ext}=20.4 Nm
To determine, the acceleration we solve the following equation for a:
Answer:
0.0665 days
Explanation:
We are given;
The mean distance from the Earth's center to the moon;a1 = 385000 km
The mean distance from the Earth's center to the space craft;a2 = 6965 km
Formula for kepplers third law is;
T² = 4π²a³/GM
However, the proportion of both distances would be;
(T1)²/(T2)² = (a1)³/(a2)³
Where;
T1 is the period of orbit of the moon around the earth. T1 has a standard value of 27.322 days
T2 is the period of the space craft orbit.
Making T2 the subject, we have;
T2 = √((T1)²×(a2)³)/(a1)³)
Thus, plugging in the relevant values;
T2 = √(27.322² × 6965³)/(385000)³
T2 = 0.0665 days
Answer:
the average speed of the blocks is 0.36 m/s
Answer:
The voltage on the secondary is 12 V while the current is 0.5 A.
Explanation:
A transformer works by changing the level of the voltage and current on a circuit using a magnetic field and two coils. The ratio by wich they are changed is dependant on the ratio of turns between the primary and secondary of the transformer. In this case we have a ratio for the voltage of:
ratio = (turns on the secondary)/(turns on the primary)
ratio = 100/1000 = 0.1
So in this case the voltage delivered to the primary will be multiplied by 0.1. We can now calculate the voltage on the secondary:
Voltage secondary = Voltage primary* ratio = 120*0.1 = 12 V
The transformer maintains roughly the same power output on both sides, since the power output on a electric circuit is given by the product of the voltage by the current on that circuit, to maintain the same power when the voltage has been droped the current must be raised by the same ratio. So we have:
Current secondary = Current primary*(1/ratio) =0.05*(1/0.1) = 0.5 A