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Maru [420]
3 years ago
9

Aliens? do you believe?To get the points go into detail :)

Physics
2 answers:
zzz [600]3 years ago
7 0

Answer:

Yes

Explanation:

There are so many planets out there that there must be habitable planets if not in our galaxy but the Universe.

Although the chances of advanced life are slim, small primitive life like microbes or sea life may still exist.

valkas [14]3 years ago
5 0

Answer:

yes

Explanation:

just like we live in our planet there are more planet and each planet there are human but we called them aliens

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Which of the following statements are true? (There may be more than one correct choice.)
Luba_88 [7]

Answer:

option (A)

Explanation:

According to the Archimede's principle, when a body s immersed partly or wholly in a liquid, it experiences an upward force which is called buoyant force. The buoyant force is equal to the loss in the weight of body.

The weight of liquid displaces by the body is equal to the loss in weight of body.

Thus, option (a) is true.

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Forest protect the soil from erosion ? True or False
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Answer:

<h2><em>True</em></h2>

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How can resistance be useful and where can they be useful?
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A wheel rotating about a fixed axis with a constant angular acceleration of 2.0 rad/s2 starts from rest at t = 0. The wheel has
irga5000 [103]

Answer:

The total linear acceleration is approximately 0.246 meters per square second.

Explanation:

The total linear acceleration (a) consist in two components, <em>radial</em> (a_{r}) and <em>tangential</em> (a_{t}), in meters per square second:

a_{r} = \omega^{2}\cdot r (1)

a_{t} = \alpha \cdot r (2)

Since both components are orthogonal to each other, the total linear acceleration is determined by Pythagorean Theorem:

a = \sqrt{a_{r}^{2}+a_{t}^{2}} (3)

Where:

r - Radius of the wheel, in meters.

\omega - Angular speed, in radians per second.

\alpha - Angular acceleration, in radians per square second.

Given that wheel accelerates uniformly, we use the following kinematic equation:

\omega = \omega_{o}+ \alpha\cdot t (4)

Where:

\omega_{o} - Initial angular speed, in radians per second.

t - Time, in seconds.

If we know that r = 0.1\,m, \alpha = 2\,\frac{rad}{s^{2}}, \omega_{o} = 0\,\frac{rad}{s} and t = 0.60\,s, then the total linear acceleration is:

\omega = \omega_{o}+ \alpha\cdot t

\omega = 1.2\,\frac{rad}{s}

a_{r} = \omega^{2}\cdot r

a_{r} = 0.144\,\frac{m}{s^{2}}

a_{t} = \alpha \cdot r

a_{t} = 0.2\,\frac{m}{s^{2}}

a = \sqrt{a_{r}^{2}+a_{t}^{2}}

a \approx 0.246\,\frac{m}{s^{2}}

The total linear acceleration is approximately 0.246 meters per square second.

3 0
3 years ago
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