Answer:
SiS2, silicone disulfide, is a linear, nonpolar compound.
Answer:
(1) Chloroplast
Explanation:
Cells of living organisms are made up of certain function-specific structures called ORGANELLES. Some organelles are present in plant cells and absent in animal cells and vice versa. In a plant cell, one notable organelle that allows it perform the photosynthetic process is the CHLOROPLAST.
However, the chloroplast is predominantly found in the LEAF part of a plant. This is because leaf cells are the site of photosynthesis. Hence, according to this question, Joe would be able to tell whether the plant cell was from the leaf or the root by looking for CHLOROPLAST as a differentiating factor in each cell.
Increase in speed, decrease in speed, and or change in direction.
Answer:
4.49dm3
Explanation:
2NH4Cl + Ca(OH)2 —> CaCl2 + 2NH3 + 2H2O
First, we need to convert 10g of ammonium chloride to mole. This is illustrated below:
Molar Mass of NH4Cl = 14 + (4x1) + 35.5 = 53.5g/mol
Mass of NH4Cl = 10g
Number of mole = Mass /Molar Mass
Number of mole of NH4Cl = 10/53.5 = 0.187mol
From the equation,
2moles of NH4Cl produced 2 moles of NH3.
Therefore, 0.187mol of NH4Cl will also produce 0.187mol of NH3
Now we can obtain the volume of NH3 produced by doing the following:
1mole of any gas occupy 24dm3
Therefore, 0.187mol of NH3 will occupy = 0.187 x 24 = 4.49dm3
Answer:
172 g Al
Step-by-step explanation:
We know we will need a balanced equation with masses and molar masses, so let’s <em>gather all the information</em> in one place.
M_r: 26.98 101.96
4Al + 3O₂ ⟶ 2Al₂O₃
m/g: 325
(a) Calculate the <em>moles of Al₂O₃
</em>
n = 325 g Al₂O₃ × 1 mol Al₂O₃ /39.10 g Al₂O₃
n = 3.188 mol Al₂O₃
(b) Calculate the <em>moles of Al
</em>
The molar ratio is (4 mol Al/2 mol Al₂O₃)
n = 3.188 mol Al₂O₃ × (4 mol Al/2 mol Al₂O₃)
n = 6.375 mol Al
(c) Calculate the <em>mass of Al</em>
m = 6.375 mol Al × (26.98 g Al/1 mol Al)
m = 172 g Al
Note: The answer can have only <em>three</em> significant figures because that is all you gave for the mass of Al₂O₃.