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LenKa [72]
3 years ago
7

The solubility of a gas in a liquid increases with increasing pressure. To understand the above statement, consider a familiar e

xample: cola. In cola and other soft drinks, carbon dioxide gas remains dissolved in solution as long as the can or bottle remains pressurized. As soon as the lid is opened and pressure is released, the CO2 gas is much less soluble and escapes into the air. The relationship between pressure and the solubility of a gas is expressed by Henry's law: S=kP, where S is concentration in M, k is the Henry's law constant in units of mol/(L⋅atm), and P is the pressure in atm. Note: Since temperature also affects the solubility of a gas in an liquid, the Henry's law constant is specific to a particular gas at a particular temperature. The following table provides some information on carbon dioxide solubility in water. S (mol/L) P (atm) k (mol⋅L−1⋅atm−1) T (∘C) 3.80×10−2 1.00 20.0 6.60×10−2 20.0 1.00 3.50×10−2 25.0 Part A What is the Henry's law constant for CO2 at 20∘C?
Chemistry
2 answers:
weeeeeb [17]3 years ago
5 0

Answer:

gukyfkuyk

Explanation:

Tanzania [10]3 years ago
3 0

Answer:

The Henry's law constant for CO2 is 3.8x10⁻²mol/L atm

Explanation:

please, the solution is in the attached Word file

Download docx
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See explanation below

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Picture 1, would be the original question. Picture 2 is the answer of it.

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8 0
3 years ago
Please help me with this question!!
mestny [16]

Answer: 824.6 g of NaCl are produced from 500.0 g of chlorine.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}  \text{Moles of} Cl_2=\frac{500.00g}{71g/mol}=7.04moles

2Na+Cl_2\rightarrow 2NaCl  

According to stoichiometry :

1 mole of Cl_2 produce = 2 moles of NaCl

Thus 7.04 moles of Cl_2 will produce=\frac{2}{1}\times 7.04=14.08moles  of NaCl

Mass of NaCl=moles\times {\text {Molar mass}}=14.08moles\times 58.5g/mol=824.26g

Thus 824.6 g of NaCl are produced from 500.0 g of chlorine.

3 0
3 years ago
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