Answer: SO₂ (Sulphur(iv)oxide)
Explanation:
<em>Oxidation:</em> Oxidation is the process involving a loss in electron, it can also mean the addition of oxygen to a substance during chemical reaction. It can also mean removal of hydrogen from a substance during chemical reaction. it can also mean addition of electropositive element and removal of electronegative element from a substance during chemical reaction.
<em>Oxidation Number:</em><em> The oxidation number of an element in any particular molecule or ion is defined as the electrical charge.</em>
Sulphur have variable oxidation states. And the oxidation number of surphur
is -2, -4 or -6, and the oxidation number of oxygen is -2.
Therefore when sulphur react with oxygen, the most likely results is sulphur(iv)oxide. (SO₂).
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A catalyst lowers the activation energy of a reaction by providing a different mechanism through which the reaction can go
I hope that's help !
Answer: 6.3x10-² moles of H20
Explanation: Solution:
Convert first the mass of O2 to moles which is 1 mole of O2 over its molar mass. The molar mass of O2 is 32. Then after that check the stoichiometric factors of both O2 and H2O.
0.252gO2 x 1mole O2/ 32 g O2 x 4 mol H2O/ 5 moles O2.
Both g of O2 and moles of O2 will be canceled out so the remaining unit is mole of H2O.
Answer:
113.69°k
Explanation:
V1=85L of helium V2=32L
T1= 29°C +273= 302°K T2=?
T2=<u>TIV2</u>
V1
T2=<u>(302)(32)</u>= <u>9664</u>
85 85
T2= 113.69°K
<span>3 elements
Nitrogen
Hydrogen
Oxygen
2 nitrogen 4 hydrogen and 3 oxygens
there are only 3 different elements</span>
