A mass hanging from a spring is set in motion and its ensuing velocity is given by v (t )equals 2 pi cosine pi t for tgreater th
an or equals 0. Assume that the positive direction is upward and s(0)equals 0.
1 answer:
Answer:
2(maximum), -2(minimum), -2(maximum).
Explanation:
V(t)= 2πcos πt--------------------------------------------------------------------------------(1).
Therefore, there is a need to integrate v(t) to get S(t).
S(t)= 2×sinπt + C ------------------------------------------------------------------------------(2).
Applying the condition given, we have s(0)= 0.
S(0)= 2sin ×π(0) + C.
Which means that; 0+C= 0. That is; C=0.
S(t)= 2 sin πt.
The mass moves to its highest positions at time,t=half(1/2=.5) and time,t=2.5.
Take note that; sin(π/2) = sin(5π/2) = 1 .
Also, the mass moves to its lowest position at time,t=(3/2); also, sin(3π/2) = -1.
Therefore, we have that 2 maximum; -2 minimum and -2 maximum.
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Here is the full question.
Saturated ethylene glycol at 1 atm is heated by a chromium-plated surface which is circular in shape and has a diameter of 200-mm and is maintained at 480 K.
At 470 K the properties of the saturated liquid are mu = 0.38 * 10-3 N. s/m^2, Cp = 3280 J/kg. K and Pr = 8.7. The saturated vapour density is p= 1.66 kg/m^3. Take the liquid to surface constants to be Cnb = 0.010 and m=4.1.
Estimate the heating power requirement and the rate of evaporation
What fraction is the power requirement of the maximum power associated with the critical heat flux
Answer:
The heating power requirement = 559.2 W
The rate of evaporation =
The fraction of the power requirement of operating heat flux to the maximum power associated with the critical heat flux is = 0.026
Explanation:
From the thermodynamics tables; we deduced the value for enthalpy at the pressure 1 atm and = 470 K for the saturated ethylene glycol.
Value for enthalpy of formation = 812 kJ/kg
Density of saturated ethylene glycol = 1111 kg/m³
Surface tension
The heat flux can be calculated by using the formula:
= 308.56 × 576.6 × 0.1
= 1.78 × 10⁴ W/m²
Now; to find the heating power requirement; we have:
=
Thus, the heating power requirement = 559.2 W
The rate of evaporation is given as:
=
=
Thus, the rate of evaporation =
To determine to what fraction in the power requirement of the maximum power is associated with the critical total flux ; we needed to first calculate the critical heat flux.
So, the calculation for the critical heat is given as:
=
= 200840.08 × 3.37
= 6.77 × 10⁵ W/m²
Finally, the fraction of the power requirement of operating heat flux to the maximum power associated with the critical heat flux is as follows:
=
=
= 0.026
Thus, the fraction of the power requirement of operating heat flux to the maximum power associated with the critical heat flux is = 0.026