1. In the laboratory, the life time of a particle moving with speed 2.8 x 10^10 cm\s is found to be 2.5 x 10^-7.
1 answer:
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<h3>Average Speed ≈ 18m/s</h3>
Explanation:
Distance : 600 m
Time : 33 seconds
Average Speed : ?
Simplify
Answer:
The kinetic energy of an electron in the beam is 5.04 keV.
Explanation:
We need to find the velocity of the electron by using the De Broglie wavelength:
Where:
λ: is the wavelength = 0.0173 nm
v: is the velocity
m: is the electron's mass = 9.1x10⁻³¹ kg
h: is the Planck constant = 6.62x10⁻³⁴ J.s
Now, we can find the kinetic energy:
Therefore, the kinetic energy of an electron in the beam is 5.04 keV.
I hope it helps you!
Answer:
a) 1273.23 A/m^2
b) 7.19*10^-5 m/s
c) 236881.7 Ohms
Explanation:
(a) To find the current density you use the following formula:
I: current in the wire
A: cross area of the wire
r: radius of the wire
(b) The electron drift speed is given by:
n: number of conduction electrons per m^3
q: charge of the electron = 1.6*10^-19C
The number of free electrons is calculated by using:
Next, you replace the values of the parameters in the equation for vd:
(c) The conductivity is given by:
You first calculate R:
Next, replace for sigma: