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Tresset [83]
3 years ago
14

CuCl2 + 2NaNO3 mc023-1.jpg Cu(NO3)2 + 2NaCl What is the percent yield of NaCl if 31.0 g of CuCl2 reacts with excess NaNO3 to pro

duce 21.2 g of NaCl?
Chemistry
2 answers:
MatroZZZ [7]3 years ago
3 0
The stoichiometric ratio of CuCl2 to NaCl is 1 is to 2. The stoichiometric ratio of 31.0 g CuCl2 is 26.95 grams of NaCl by converting the amount of CuCl2 to mole and multiplying by 0.5 and molar mass of NaCl.This amount is equal to 78.65% yield.
Lera25 [3.4K]3 years ago
3 0
The answer is D 78.7%
just finished the test
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