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Tresset [83]
3 years ago
14

CuCl2 + 2NaNO3 mc023-1.jpg Cu(NO3)2 + 2NaCl What is the percent yield of NaCl if 31.0 g of CuCl2 reacts with excess NaNO3 to pro

duce 21.2 g of NaCl?
Chemistry
2 answers:
MatroZZZ [7]3 years ago
3 0
The stoichiometric ratio of CuCl2 to NaCl is 1 is to 2. The stoichiometric ratio of 31.0 g CuCl2 is 26.95 grams of NaCl by converting the amount of CuCl2 to mole and multiplying by 0.5 and molar mass of NaCl.This amount is equal to 78.65% yield.
Lera25 [3.4K]3 years ago
3 0
The answer is D 78.7%
just finished the test
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Please Help Me!
S_A_V [24]

Answer:

The answer to your question is      SO₂   +   3H₂    ⇒     H₂S   + 2H₂O

Explanation:

Reaction

                                SO₂   +   H₂    ⇒     H₂S   +  H₂O

                      Reactants           Elements            Products

                              1                   Sulfur                    1

                               2                  Hydrogen               4

                              2                   Oxygen                   1

This reaction is unbalanced so we need to balance it.

                              SO₂   +   3H₂    ⇒     H₂S   + 2H₂O

                      Reactants           Elements            Products

                              1                   Sulfur                   1

                              6                  Hydrogen               6

                              2                   Oxygen                  2

Now, the reaction is balanced

3 0
3 years ago
Which arrows represents the phase transitions in which he's energy is gained
prisoha [69]

Answer:

Do you have a picture of this?

6 0
3 years ago
compound 1 contains 15.0g of hydrogen and 120.0g oxygen. What is the percent compound of each element?
allsm [11]

Note down the formula below

\boxed{\sf Mass\%\;of\; element=\dfrac{Mass\:of\:the\: element}{Mass\;of\:the\: compound}\times 100}

Mass of the compound

\\ \sf\longmapsto 15+120=135g

Mass % of Hydrogen:-

\\ \sf\longmapsto \dfrac{15}{135}\times 100

\\ \sf\longmapsto \dfrac{1}{9}\times 100

\\ \sf\longmapsto 11.1\%

Mass % of Oxygen:-

\\ \sf\longmapsto \dfrac{120}{135}\times 100

\\ \sf\longmapsto \dfrac{8}{9}\times 100

\\ \sf\longmapsto 88.9\%

8 0
3 years ago
Approximately what percentage of a human's DNA is used for coding Information for the synthesis of proteins?
skelet666 [1.2K]
I’m pretty sure it is 25 % :))
4 0
3 years ago
A chemist has 3.55x1022 molecules of nitrogen monoxide. How
Alina [70]

Answer:

<h2>0.059 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{3.55 \times  {10}^{22} }{6.02 \times  {10}^{23} }  \\  = 0.05897...

We have the final answer as

<h3>0.059 moles</h3>

Hope this helps you

6 0
3 years ago
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