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butalik [34]
3 years ago
9

In a chemical reaction, the final amount of the products is determined by the

Chemistry
1 answer:
lukranit [14]3 years ago
4 0
<span>E.) In a chemical reaction, the final amount of the products is determined by the  "None of the above"

[ Depends on all physical conditions & chemical situation ]

Hope this helps!</span>
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A sample of the chiral molecule limonene is 62% enantiopure. what percentage of each enantiomer is present? what is the percent
ikadub [295]

The mixture contains 62 % one isomer and 38 % the enantiomer.

Let’s say that the mixture contains 62 % of the (<em>R</em>)-isomer.

Then % (<em>S</em>) = 100 % -62 % = 38 %

ee = %  (<em>R</em>) - % (<em>S</em>) = 62 % -38 % = 24 %


6 0
3 years ago
Read 2 more answers
The following data were obtained in a kinetics study of the hypothetical reaction A + B + C → products. [A]0 (M) [B]0 (M) [C]0 (
Vladimir [108]

Answer:

B. First order, Order with respect to C = 1

Explanation:

The given kinetic data is as follows:

A + B + C → Products

     [A]₀     [B]₀    [C]₀       Initial Rate (10⁻³ M/s)

1.   0.4      0.4     0.2       160

2.  0.2      0.4      0.4       80

3.   0.6     0.1       0.2       15

4.   0.2     0.1       0.2        5

5.   0.2     0.2      0.4       20

The rate of the above reaction is given as:

Rate = k[A]^{x}[B]^{y}[C]^{z}

where x, y and z are the order with respect to A, B and C respectively.

k = rate constant

[A], [B], [C] are the concentrations

In the method of initial rates, the given reaction is run multiple times. The order with respect to a particular reactant is deduced by keeping the concentrations of the remaining reactants constant and measuring the rates. The ratio of the rates from the two runs gives the order relative to that reactant.

Order w.r.t A : Use trials 3 and 4

\frac{Rate3}{Rate4}= [\frac{[A(3)]}{[A(4)]}]^{x}

\frac{15}{5}= [\frac{[0.6]}{[0.2]}]^{x}

3 = 3^{x} \\\\x =1

Order w.r.t B : Use trials 2 and 5

\frac{Rate2}{Rate5}= [\frac{[B(2)]}{[B(5)]}]^{y}

\frac{80}{20}= [\frac{[0.4]}{[0.2]}]^{y}

4 = 2^{y} \\\\y =2

Order w.r.t C : Use trials 1 and 2

\frac{Rate1}{Rate2}= [\frac{[A(1)]}{[A(2)]}]^{x}[\frac{[B(1)]}{[B(2)]}]^{y}[\frac{[C(1)]}{[C(2)]}]^{z}

we know that x = 1 and y = 2, substituting the appropriate values in the above equation gives:

\frac{160}{80}= [\frac{[0.4]}{[0.2]}]^{1}[\frac{[0.4]}{[0.4]}]^{2}[\frac{[0.2]}{[0.4]}]^{z}

1 = (0.5)^{z}

z = 1

Therefore, order w.r.t C = 1

8 0
4 years ago
Acids taste<br> a. sweet. <br> c. bitter. <br> b. sour. <br> d. salty
Gnesinka [82]
The answer is (b) for example lemon juice is an acid and it tastes sour.
Hope this helps :).
4 0
3 years ago
How many molecules of O2 are in 153.9 g O2?
MrRissso [65]

Answer:

2.895*10^24

Explanation:

mass of Oxygen give = 153.9g

molar mass of O2 molecule = 16*2=32g/mol

n= mole

To find the mole

n= mass/ molar mass

n= 153.9/32

n=4.81mol.

To find the number of molecules of o

Nm= number of molecule

Nn = Number of mole

NA = number of Avogados

Nm= Nn * NA

Nm= 4.81 *6.02*10^23

Nm= 2.895*10^24

3 0
3 years ago
Easy question please help. DUE IN 15 MINUTES. Calculate the frequency of light that has a wavelength of 9.75 x 10^-7 m.
mart [117]

Answer:

3.077 × 10¹⁴ Hz

Explanation:

f = ?

wavelength = 9.75 × 10-⁷m

using the formula,

c = wavelength × frequency

f = c/wavelength

but c(speed of light) = 3×10⁸m/s

f = 3 × 10⁸/9.75 × 10-⁷

f = 3.077 × 10¹⁴ s-¹

5 0
3 years ago
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