A solution has a pOH of 7. 1 at 10∘c. Then the pH of the solution given that kw=2. 93×10−15 at this temperature is 7.4 .
It is given that,
pOH of solution = 7.1
Kw =2.93×10^(-15)
Firstly, we will calculate the value of pKw
The expression which we used to calculate the pKw is,
pKw=-log [Kw]
Now by putting the value of Kw in this expression,
pKw =−log{2.93×10^(-15)}
pKw =15log(2.93)
pKw=14.5
Now we have to calculate the pH of the solution.
As we know that,
pH+pOH=pKw
Now put all the given values in this formula,
pH+7.1=14.5
pH=7.4
Therefore, we find the value of pH of the solution is, 7.4.
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CaSO4(s) might be an improperly capitalized: CAsO4(S), CaSO4(S)
Balanced equation:
K2SO4(aq) + CaI2(aq) = CaSO4(s) + 2 KI(aq)
Reaction type: double replacement.
Explanation:
Steps followed to practice laboratory safety during the experiment are as follows.
- Used tongs or a test tube holder to hold materials over the Bunsen burner flame.
- Wore gloves and goggles.
- Made careful observations of the products and reactants.
- Did not smell the gases produced.
When we heat a test tube over bunsen flame then the tube gets hot and when we hold it with bare hands then out hands will burn. Therefore, it is advised to hold test tube with the help of tongs or a holder so that our hands did not burn.
We should also wear gloves and goggles so that any acid would not spill directly on our hands, skin and eyes as it can affect or damage the skin severely.
Careful observations were made so that correct calculations about the experiment can be carried out.
It is also advised that we should not smell the gases produced but gases move freely from one place to another in a laboratory or any where else.
So, we can try to avoid it by covering our mouth with a cloth but we cannot stop it. If we keep on inhaling the gases produced in a laboratory then it can also lead to severe disease or defect in the human body.
Answer:
See which of your answer choices are comparable and what you can contrats them with
Explanation:
YEET
