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vagabundo [1.1K]
3 years ago
9

A force of 49N causes a box to move with an acceleration of 7m/s2. Find the mass of the object

Physics
1 answer:
Tju [1.3M]3 years ago
8 0

Answer:

<h3>The answer is 7 kg</h3>

Explanation:

To find the mass of the object given the force and acceleration we use the formula

m =  \frac{f}{a}  \\

where

f is the force

a is the acceleration

m is the mass

From the question

f = 49 N

a = 7 m/s²

We have

m =  \frac{49}{7}  \\

We have the final answer as

<h3>7 kg</h3>

Hope this helps you

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The momentum of an object is equivalent to the product of the object's mass and velocity. Computing the momentum for each ball:
A- 15 * 0.7 = 10.5
B- 5.5 * 1.2 = 6.6
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I drove from Oklahoma to California (1452.9 miles) in 23 hours? What was my average speed?
storchak [24]

Answer:

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Explanation:

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2 years ago
A hamster eats a carrot before using its hamster wheel. The hamster wheel is connected to a generator which powers a light bulb.
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Explanation:

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Now the hamster starts using his wheel, then he "transforms" the chemical energy into mechanical energy.

Now the mechanical energy is connected to a generator, this means that the mechanical energy (the rotation of the wheel) is being converted into electrical energy.

And we know that there is a light bulb powered by this electrical energy, then we have electrical energy being transformed into radiant energy.

Then the correct option is:

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6 0
3 years ago
Three forces are applied to a solid cylinder of mass 12 kg (see the drawing). The magnitudes of the forces are F1 = 15 N, F2 = 2
crimeas [40]

Answer:

α = 13.7 rad / s²

Explanation:

Let's use Newton's second law for rotational motion

         ∑ τ = I α

         

we will assume that the counterclockwise turns are positive

         F₁  0 + F₂ R₂ - F₃ R₃ = I α

give us the cylinder moment of inertia

        I = ½ M R₂²

         

        α = (F₂ R₂ - F₃ R₃)  \frac{2}{M R_2^2}

let's calculate

        α = (24  0.22 - 13  0.10) \frac{2}{12 \ 0.22^2}2/12 0.22²

        α = 13.7 rad / s²

6 0
3 years ago
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