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3 years ago

Glaciers around the world have been _____. A. shrinking B. increasing in size C. increasing in density D. decreasing in density

Physics

1 answer:

erik [133]3 years ago

3 0

<h3>✽ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>

➷ The correct answer is A. Shrinking

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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A woman is standing in the ocean, and she notices that after a wave crest passes, five more crests pass in a time of 54.0 s. The

timama [110]

Answer:

a) f=0.1 Hz ; b) T=10s

c)λ= 36m

d)v=3.6m/s

e)amplitude, cannot be determined

Explanation:

Complete question is:

Determine, if possible, the wave's (a) frequency, (b) period, (c) wavelength, (d) speed, and (e) amplitude.

Given:

number of wave crests 'n'= 5

pass in a time't' 54.0s

distance between two successive crests 'd'= 36m

a) Frequency of the waves 'f' can be determined by dividing number of wave crests with time, so we have

f=n/t

f= 5/ 54 => 0.1Hz

b)The time period of wave 'T' is the reciprocal of the frequency

therefore,

T=1/f

T=1/0.1

T=10 sec.

c)wavelength'λ' is the distance between two successive crests i.e 36m

Therefore, λ= 36m

d) speed of the wave 'v' can be determined by the product of frequency and wavelength

v= fλ => 0.1 x 36

v=3.6m/s

e) For amplitude, no data is given in this question. So, it cannot be determined.

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3 years ago

The velocity v(t) in the table below is increasing for 0_t_12.

katen-ka-za [31]

<span>When n=4 subdivisions distance traveled = 40 X 12 = 480

When n=2 subdivisions distance traveled = 30 X 6 = 180

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.
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3 years ago

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An enemy spaceship is moving toward your starfighter with a speed of 0.400 c , as measured in your reference frame. The enemy sh

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The answer is (a) 0.859c (b) 31s

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Consider a cloudless day on which the sun shines down across the United States. If 2073 kJ of energy reaches a square meter ( m

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The total amount of energy per hour is $2.039\cdot 10^{16} kJ$