Answer:
<em>a. t = 2.02 s
</em>
<em>b. d = 20.2 m</em>
Explanation:
<u>Horizontal Motion
</u>
If an object is thrown horizontally from a height h with a speed v, it describes a curved path ruled exclusively by gravity until it eventually hits the ground.
The time the object takes to hit the ground can be calculated as follows:
The time does not depend on the initial speed.
The range or maximum horizontal distance traveled by the object can be calculated by the equation:
The man standing on the edge of the h=20 m cliff throws a rock with an initial horizontal speed of v=10 m/s.
a.
The time taken by the rock to reach the ground is:
t = 2.02 s
b.
The range is:
d = 20.2 m
Answer:
F=m(a) 3.111
Explanation:
So to find the acceleration you would have to reverse the problem, a=F/m
In the balanced nuclear reaction of uranium 235, we have thorium 231, helium atom and energy released at the right of the equation
<h3>
Balanced nuclear reaction of Uranium</h3>
The balanced nuclear reaction of uranium is determined as follows;
Thus, in the balanced nuclear reaction of uranium 235, we have thorium 231, helium atom and energy released at the right of the equation while uranium 235 is on the left hand side of the nuclear reaction equation.
Learn more about nuclear reaction here:
brainly.com/question/25387647
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Answer:
The charge is 0.056 nC.
Explanation:
Given that,
Electric field = 2000 N/C
Distance = 5.0 cm
We need to calculate the charge density
Using formula of charge density
Put the value into the formula
We need to calculate the charge in 1.0 cm
Using formula of charge
Hence, The charge is 0.056 nC.
Answer
given,
v = (6 t - 3 t²) m/s
we know,
position of the particle
integrating both side
x = 3 t² - t³
Position of the particle at t= 3 s
x = 3 x 3² - 3³
x = 0 m
now, particle’s deceleration
a = 6 - 6 t
at t= 3 s
a = 6 - 6 x 3
a = -12 m/s²
distance traveled by the particle
x = 3 t² - t³
at t = 0 x = 0
t = 1 s , x = 3 (1)² - 1³ = 2 m
t = 2 s , x = 3(2)² - 2³ = 4 m
t = 3 s , x = 0 m
total distance traveled by the particle
D = distance in 0-1 s + distance in 1 -2 s + distance in 2 -3 s
D = 2 + 4 + 2 = 8 m
average speed of the particle
