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alisha [4.7K]
4 years ago
11

One major advantage of alternating current over direct current is that you can use alternating current with a device known as a

transformer. The reason why alternating current works in transformers but direct current does not is?
Physics
2 answers:
Oksanka [162]4 years ago
6 0

transformer makes use of mutual induction for its operation in which change in magnetic field in one coil due to variation of current , induces voltage in the other coil. so changing magnetic field in the primary coil is very much needed for the transformer. Alternating current is a current which varies with time , hence it is suitable to produce changing magnetic field in the primary coil. on the other hand , the direct current remains constant all the time. hence can not produce a changing magnetic field. so DC current is not useful for transformers.

marin [14]4 years ago
4 0

On USATestprep its D

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A wheel is rotating at a rate of 2.0 rev every 3.0s. through what angle, in radian , does the wheel rotate in 1.0s?​
igomit [66]

Answer:

4 \pi

Explanation:

First of all, let's convert 2.0 rev into radians:

1.0 rev = 2\pi rad\\2.0 rev = 4 \pi rad

This means that the angular speed of the wheel is

\omega = 2.0 rev/s = 4 \pi rad/s

The angle through which the wheel rotates in a time t is given by

\theta=\omega t

And substituting t=1.0 s, we find

\theta=(4\pi rad/s)(1.0 s)=4 \pi rad

7 0
3 years ago
The plates of a parallel plate capacitor are separated by d = 1.6 cm. The potential of the negative plate is 0 V, and the potent
yaroslaw [1]

Answer:

The electric field between the plates is 1875 V/m.

Explanation:

Given that,

Separated d=1.6 cm

Potential of negative plate = 0 V

Potential halfway between the plates = 15 V

We need to calculate the total potential

Using formula of potential

V=2\times\text{Potential halfway between the plates}

Put the value into the formula

V=2\times15

V=30\ V

We need to calculate the electric field between the plates

Using formula of electric field

E=\dfrac{V}{d}

E=\dfrac{30}{1.6\times10^{-2}}

E=1875\ V/m

Direction is negative as the field always points from positive  to negative plate

Hence, The electric field between the plates is 1875 V/m.

5 0
3 years ago
How many protons are in one kg of lead? b) How many electrons are in one kg of lead? c) What is the total negative charge of the
mina [271]

Answer:

Number of protons = 2.3836\times 10^{26}

Number of electrons = 2.3836\times 10^{26}

Charge on these electrons = -3.8185\times 10^{7}\ C

Explanation:

1 atom of lead contains 82 protons and 82 electrons

1 mole = 6.023\times 10^{23} atoms

Thus,

1 mole of lead contains 82\times 6.023\times 10^{23} protons

Also, 1 mole of lead weighs 207.2 g

So,

207.2 g of lead contains 82\times 6.023\times 10^{23} protons

1 kg = 1000 g

So,

1000 g or 1 kg of lead contains \frac {82\times 6.023\times 10^{23}}{207.2}\times 1000 protons

<u>Number of protons = 2.3836\times 10^{26}</u>

Also, for neutral atom, number of protons = number of electrons.

Thus,

<u>Number of electrons = 2.3836\times 10^{26}</u>

Also,

Charge of 1 electron = - 1.602\times 10^{-19}\ C

Charge on these electrons = -2.3836\times 10^{26}\times 1.602\times 10^{-19}\ C

<u>Charge on these electrons = -3.8185\times 10^{7}\ C</u>

3 0
3 years ago
A box slides down a frictionless ramp.if it starts at rest, what is it’s speed at the bottom?
zhenek [66]

8.854 m/s is the speed of the box after it reaches bottom of the ramp.

<u>Explanation</u>:

From the figure we came to know that height of the block is 4 m.

We know that,

Total "initial energy of an object" = Total "final energy of an object "

Total "initial energy of an object" is = "sum of potential energy" and "kinetic energy" of an object at its initial position.

\text { "g" acceleration due to gravity is } 9.8 \mathrm{m} / \mathrm{s}^{2}

\text { Total initial energy }=\mathrm{m} \times \mathrm{g} \times \mathrm{h}_{\mathrm{i}}+\frac{1}{2} \mathrm{m} v_{i}^{2}

Initial velocity is “0” as the object does not have starting speed

\text { Height of the block where the object is placed initially }\left(h_{i}\right) \text { is } 4 \mathrm{m} \text { . }

\text { Total initial energy }=\mathrm{m} \times 9.8 \times 4+\frac{1}{2} \mathrm{m} 0^{2}

Total initial energy = 39.2 × m

\text { Total final energy }=\mathrm{m} \times \mathrm{g} \times \mathrm{h}_{\mathrm{f}}+\frac{1}{2} m v_{f}^{2}

\text { We need to find final velocity } v_f

\text { Height of the block where the object is travelled to bottom (h_) is } 0 \mathrm{m} \text { . }

\text { Total final energy }=\mathrm{m} \times 9.8 \times 0+\frac{1}{2} m v_{f}^{2}

Now,  Total initial energy of an object = Total final energy of an object

39.2 \times \mathrm{m}=0.5 \mathrm{m} v_{f}^{2}

\frac{39.2}{0.5}=v_{f}^{2}

v_{f}^{2}=78.4

v_{f}=\sqrt{78.4}

v_{f}=8.854 \mathrm{m} / \mathrm{s}

Final speed is 8.854 m/s.

3 0
3 years ago
While traveling south on an expressway, a car traveling 60 mph (miles per hour) slows down to 30 mph in 12 minutes due to traffi
Cloud [144]
10mph is the acceleration that u are looking for
5 0
3 years ago
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