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4 years ago

Name the following ionic compounds: (a) Na2SO4, (b)Cu(NO3)2 (c) Fe2(CO3)3

Chemistry

1 answer:

Sindrei [870]4 years ago

5 0

Answer and Explanation:

(a) $Na_2So_4$ : its chemical name is sodium sulfate in which sodium is present as $Na_2^+$ and sulfate is present as $So_4^{2-}$

(b) $Cu(NO_3)_2$ : Its chemical name is copper nitrate which is a inorganic compound which is mostly crystalline in nature

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Which of the following could be described as exotic? *

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A rare type of flower

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3 years ago

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Mechanical layers of the earth is divided by what they are made of. True or False?

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The answer is 19 terms ok ok ok

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3 years ago

What is the ratio of the magenta phenolphthalein concentration to the colorless phenolphthalein concentration ([magenta phenolph

lilavasa [31]

Answer:

$\frac{[magenta\ phenolphthalein]}{[colorless\ phenolphthalein]}=31.62$

Explanation:

Considering the Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution as:

$pH=pKa+\log\frac{[base]}{[acid]}$

Where Ka is the dissociation constant of the acid.

pKa of phenolphthalein = 9.40

pH = 10.9

So,

$10.9=9.40+\log\frac{[magenta\ phenolphthalein]}{[colorless\ phenolphthalein]}$

$\frac{[magenta\ phenolphthalein]}{[colorless\ phenolphthalein]}=31.62$

4 0

3 years ago

When ammonia is mixed with hydrogen chloride (HCl), the white solid ammonium chloride (NH4Cl) is produced. Suppose 10.0 g ammoni

Alex_Xolod [135]

Answer:

There will remain 5.33 grams of NH3 and there will be produced 14.66 grams NH4Cl

Explanation:

Step 1: Data given

Mass of ammonia = 10.0 grams

Mass of hydrogen chloride = 10.0 grams

Molar mass of ammonia = 17.03 g/mol

Molar mass of hydrogen chloride = 36.46 g/mol

Step 2: the balanced equation

NH3 + HCl → NH4Cl

Step 3: Calculate moles NH3

Moles NH3 = mass NH3 / molar mass NH3

Moles NH3 = 10.0 grams / 17.03 g/mol

Moles NH3 = 0.587 moles

Step 4: Calculate moles HCl

Moles HCl = 10.0 grams / 36.46 g/mol

Moles HCl = 0.274 moles

Step 5: Calculate limiting reactant

For 1 mol NH3 we need 1 mol HCl to produce 1 mol NH4Cl

HCl is the limiting reactant. It will completely be consumed. (0.274 moles)

NH3 is in excess. There will remain 0.587 - 0.274 = 0.313 moles

This is: 0.313 moles * 17.03 = 5.33 grams

Step 6: Calculate moles NH4Cl

For 1 mol NH3 we need 1 mol HCl to produce 1 mol NH4Cl

For 0.274 moles HCl we need 0.274 moles NH4Cl

Step 7: Calculate mass of NH4Cl

Mass NH4Cl = moles NH4Cl * molar mass NH4Cl

Mass NH4Cl = 0.274 moles * 53.49 g/mol

Mass NH4Cl = 14.66 grams

There will remain 5.33 grams of NH3 and there will be produced 14.66 grams NH4Cl

4 0

4 years ago

How much heat, in kJ, is required to raise the temperature of 50 g of water by 5.53°C? (Round to the nearest 10 kJ, and enter on

Triss [41]

Answer:

$Q=1.16kJ$

Explanation:

Hello,

in this case, the required heat to increase the water by 5.53 °C is computed by using the mass, heat capacity and change in temperature during the process:

$Q=mCp\Delta T$

Thus, for the given data we compute it in kJ:

$Q=50g*4.186\frac{J}{g*\°C}*(5.53\°C)*\frac{1kJ}{1000J} \\\\Q=1.16kJ$

Best regards.

5 0

3 years ago