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nika2105 [10]
4 years ago
5

When 0.110 mol of aluminum are allowed to react with an excess of chlorine gas, Cl2, how many moles of aluminum chloride are pro

duced?
2Al + 3Cl2= 2AlCl3
Chemistry
1 answer:
olganol [36]4 years ago
6 0

0.11 moles of Aluminium chloride

<u>Explanation:</u>

<u />

Given:

2Al + 3Cl₂ → 2AlCl₃

According to the balanced equation:

2 moles pf Aluminium form 2 moles of Aluminium chloride.

So, 1 mole of Al will form 1 mole of Aluminium chloride.

0.11 mole of Al is present.

So, 0.11 mol of Al will form 0.11 mol of Aluminium chloride.

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An element A has an atomic number of 11 and another element B has an atomic number 17 (A
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The valences of metal x,y and z are 1,2 and 3 respectively. What are the formulae of their;a) hydroxides, b) sulphates, c) hydro
Rina8888 [55]

Answer:

See answer below

Explanation:

AS we know that the valence for those metals X, Y, and Z are 1, 2 and 3, we can determine the formula of each compound.

1. Hydroxides.

An hydroxide is formed when an oxyde of a metal reacts with water. When this happens, the general molecular formula is:

Meₐ(OH)ₙ

Where:

a: valence or charge of the hydroxide (Which is -1)

n: valence of the metal.

Following this, the formula for X, Y and Z would be:

XOH

Y(OH)₂

Z(OH)₃

2. Sulphates

Sulphates follow a similar rule of hydroxide in the general molecular formula, but instead of having a charge of -1, it has a charge of -2 so:

Mₐ(SO₄)ₙ

So, following the rule:

X₂SO₄

Y₂(SO₄)₂ ------> YSO₄

Z₂(SO₄)₃

3. Hydrogens

Following the same rule as the previous, hydrogens works with a charge of -1, so:

MₐHₙ

Then:

XH

YH₂

ZH₃

4. Carbonates.

This follows the same rule as sulphates, with the same charge so:

Mₐ(CO₃)ₙ

Then:

X₂CO₃

YCO₃

Z₂(CO₃)₃

5. Nitrates

Follow the same rule as the hydroxides, with the same charge of -1.

Mₐ(NO₃)ₙ

Then:

XNO₃

Y(NO₃)₂

Z(NO₃)₂

6. Phosphates

In the case of phosphates, these have a charge of -3 so:

Mₐ(PO₄)ₙ

Then:

X₃PO₄

Y₃(PO₄)₂

Z₃(PO₄)₃ ----> ZPO₄

Hope this helps

6 0
3 years ago
Two samples of a compound containing elements a and b are decomposed. the first sample produces 15 g of a and 35 g of
Alborosie

According to law of definite proportion, for a compound, elements always combine in fixed ratio by mass.

The formula of compound remains the same, let it be a_{x}b_{y} where, a and b are two different elements.

Since, the ratio of mass remains the same , calculate the ratio of masses of element a and b in both cases

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rearranging,

y=\frac{10\times 35}{15}=23.3

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3 0
3 years ago
What is the volume of the sample at stp?
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