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nika2105 [10]
3 years ago
5

When 0.110 mol of aluminum are allowed to react with an excess of chlorine gas, Cl2, how many moles of aluminum chloride are pro

duced?
2Al + 3Cl2= 2AlCl3
Chemistry
1 answer:
olganol [36]3 years ago
6 0

0.11 moles of Aluminium chloride

<u>Explanation:</u>

<u />

Given:

2Al + 3Cl₂ → 2AlCl₃

According to the balanced equation:

2 moles pf Aluminium form 2 moles of Aluminium chloride.

So, 1 mole of Al will form 1 mole of Aluminium chloride.

0.11 mole of Al is present.

So, 0.11 mol of Al will form 0.11 mol of Aluminium chloride.

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ki77a [65]
54.15 g
First you start out with the equation n=cv (n= moles, c=molarity, v= volume)
You’re going to multiply 0.10M by 3.30L to get an answer of 0.33 moles of Ca(NO3)2
From there you’re gonna convert the moles to grams to get your answer, first you have to find the molar mass of Ca(NO3)2
This can be done by finding adding the molar mass of each individual substance
The answer you should get for the molar mass is 164.1 g
From there just multiply the number of moles you calculated (0.33 mol) by the molar mass (164.1 g) and your answer is going to be 54.15 g Ca(NO3)2
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