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butalik [34]
3 years ago
11

A typical person has an average heart rate of 75.0 beats/min. Calculate the following a)How many beats does she have in 7.0 year

s? b) How many beats in 7.000 years? Pay close attention to significant figures in this question.
Chemistry
2 answers:
Nuetrik [128]3 years ago
7 0

Answer:

a) Beats in 7.0 years = 2.7 \times 10^8

b) Beats in 7.000 yrs= 2.759 \times 10^8

Explanation:

Step 1

Calculation of no. of min. in 7 year

Days in a year = 365

Hrs in a day = 24

Min. in a 1 hr = 60

Min. in a day = 60 × 24

Min. in a year = 60 × 24 × 365

Min. in 7 years

               = 60 × 24 × 365 × 7

               = 3679200 min.

a) Beats in 7.0 years

Heart rate = 75.0 beats/min.

Beats in 7.0 yrs

             = 75.0 × 3679200

             = 275940000 beats

No. of significant figure = 2

Answer has to be reported in 2 significant digits.

Beats in 7.0 years = 2.7 \times 10^8

a) Beats in 7.000 years

Beats in 7.000 yrs = 275940000 beats

No. of significant figure in 7.000 = 4

Answer has to be reported in 4 significant figures

So, no. of beats in 7.000 yrs= 2.759 \times 10^8

hram777 [196]3 years ago
5 0

Let us first convert years to minute.

7 years * (365 days / year) * (24 hours / day) * (60 minutes / hour) = 3,679,200 minutes

 

a. beats = 75.0 beats/min * 3,679,200 minutes

beats = 275,940,000 beats

Since the original given is 7.0 years (2 significant figures), therefore:

beats = 270,000,000 beats

 

b beats = 75.0 beats/min * 3,679,200 minutes

beats = 275,940,000 beats

Since the original given is 7.000 years (4 significant figures), therefore:

<span>beats = 275,900,000 beats</span>

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If an atom has sp3d2 hybridization in a molecule:
never [62]

Answer:

a. the maximum number of σ bonds that the atom can form is 4

b. the maximum number of p-p bonds that the atom can form is 2

Explanation:

Hybridization is the mixing of at least two nonequivalent orbitals, in this case, we have the mixing of one <em>s, 3 p </em> and <em> 2 d </em> orbitals. In hybridization the number of hybrid orbitals generated  is equal to the number of pure atomic orbital, so we have 6 hybrid orbital.

The shape of this hybrid orbital is octahedral (look the attached image) , it has 4 orbital located in the plane and 2 orbital perpendicular to it.

This shape allows the formation of maximum 4 σ bond, because σ bonds are formed by orbitals overlapping end to end.

And maximum 2 p-p bonds, because p-p bonds are formed by sideways overlapping orbitals. The atom can form one with each one of the orbitals located perpendicular to the plane.

4 0
3 years ago
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Which notation represents the largest atomic radius?<br><br> Cl<br><br> F<br><br> F−<br><br> Cl−
hichkok12 [17]

Answer:

Cl⁻

Explanation:

Definition of atomic radii

The atomic radius is the distance between center of two bonded atoms.

Trend along period:

As we move from left to right across the periodic table the number of valance electrons in an atom increase.The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases.

Trend along group:

In group by addition of electron atomic radii increase from top to bottom due to increase in atomic number and addition of extra shell.

In this way Cl⁻ will have the largest atomic radii because one extra electron is added and its atomic number is already greater than fluorine.

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3 years ago
Assuming 100% dissociation, calculate the freezing point and boiling point of 1.22 m SnCl₄(aq). Constants may be found here.
Gekata [30.6K]

Answer:

T° freezing solution → -11.3°C

T° boiling solution → 103.1 °C

Explanation:

Assuming 100 % dissociation, we must find the i, Van't Hoff factor which means "the ions that are dissolved in solution"

This salt dissociates as this:

SnCl₄ (aq)  →   1Sn⁴⁺ (aq)  +   4Cl⁻  (aq)   (so i =5)

The formula for the colligative property of freezing point depression and boiling point elevation are:

ΔT = Kf . m . i

where ΔT = T° freezing pure solvent - T° freezing solution

ΔT = Kb . m . i

where ΔT = T° boiling solution - T° boiling pure solvent

Freezing point depression:

0° - T° freezing solution = 1.86°C/m . 1.22 m . 5

T° freezing solution = - (1.86°C/m . 1.22 m . 5) → -11.3°C

Boiling point elevation:

T° boiling solution - 100°C = 0.512 °C/m . 1.22 m . 5

T° boiling solution = (0.512 °C/m . 1.22 m . 5) + 100°C → 103.1 °C

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High pressure and low temperature.

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