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damaskus [11]
3 years ago
5

A 12 kg object speeds up from an initial velocity of 10 m:s-1

Physics
1 answer:
amid [387]3 years ago
5 0

Momentum = m • v

Original momentum = m • 10 m/s north

Final momentum = m • 15 m/s north

Change = m • (15 - 10) m/s north

Change = m • +5 m/s north

Change = +60 kg-m/s north

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Answer:

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Explanation:

a)

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a_{rad}=\omega r^{2}

with r the radius and ω the amgular velocity, in or case a_rad=3.5g so:

3.5g=\omega r^{2} and g=9.8\frac{m}{s^{2}}

solving for ω:

\omega=\frac{3.5g}{r^2}=\frac{3.5*9.8}{4.2^2}

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v=\omega r =(1.94)(4.7)

v= 9.12\frac{m}{s}

c) The apparent weigth is pointing towards the center of the circle, becuse angular acceleration is pointing in that direction.

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It makes it lighter when its closer and heavier when its farther way.

Explanation:

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