Question

A triangle with equal sides of length 1.0 x 103 m has -2.0 C charged objects at each corner. Determine the electrical force (magnitude and direction) exerted on the object at the top corner due to the two objects at the base of the triangle.

Answer 1

Answer:

62353.8 N

The direction of the force is along + y axis

Explanation:

A triangle with equal sides definitely has the same angle; If the angle is x & we have 3 angle in a triangle, then :

3x = 180°

x = $\frac{180}{3}$

x = 60°

Now; half of it = $\frac{60}{2}$

= 30°

Evidently;  θ = 30°

NOW, the electrical force (magnitude and direction) exerted on the object at the top corner due to the two objects at the base of the triangle can be determined by using the formula:

$F = \frac{2kq^2}{L^2} cos \theta$

$F = \frac{2*9*10^9*(-2.0^2)}{1.0^2*10^6} cos 30^0$

F = 62353.8 N

The force is directed along + y axis due to the positive charge on the force and since the force is being exerted at the top corner to the base.