Answer:
The magnitude of the electric field is
Explanation:
Given that,
Time t = 2.10 s
Speed = 160 m/s
Specific charge =Ratio of charge to mass = 0.100 C/kg
We need to calculate the acceleration
Using equation of motion
Put the value into the formula
We need to calculate the magnitude of the electric field
Using formula of electric field
Put the value into the formula
The direction is upward.
Hence, The magnitude of the electric field is
Answer:
Speed of electron when their separation increased by a factor of 4.10 is 9.41 x 10⁵ m/s .
Explanation:
The electric potential energy is given by the relation :
Here q₁ and q₂ are the two charge particles and r is the distance between them and k is electric constant.
In this case, there are two electrons which are separated by the distance 4.32 x 10⁻¹⁰ m.
Let e be the electron charge and r₁ be the distance between them. Then, the initial electric potential energy is :
Now, the distance between the electrons increases by the factor of 4.10. Let r₂ be the new distance between them i.e. r₂ = 4.10 r₁.
Thus, the new electric potential energy is :
Applying law of conservation of energy :
ΔU = ΔK
Here ΔU is change in electric potential energy and ΔK is change in kinetic energy.
( U₁ - U₂ ) = ( K₂ - K₁ )
Here K₂ and K₁ are initial and final kinetic energy of electron.
Since, the electron initially is at rest, so its initial kinetic energy is zero. Thus, the above equation becomes:
K₂ = U₁ - U₂
Here m and v are the mass and final speed of electron respectively.
Substitute 9.1 x 10⁻³¹ kg for m, 9 x 10⁹ N m² C⁻² for k, 1.6 x 10⁻¹⁹ C for e and 4.32 x 10⁻¹⁰ m for r₁ in the above equation.
v = 9.41 x 10⁵ m/s