Question

A person throws a ball straight up into the air with a speed of 7.3m/s. How high does the ball go?

Answer 1

Answer:

2.6645m

Explanation:

applying motion equations we can find the answer,

$v^{2}=u^{2} +2as$

Let assume ,

u = starting speed(velocity)

v = Final speed (velocity)

s =  distance traveled

a = acceleration

by the time of reaching the highest point subjected to the gravity , the speed should be equal to zero

we consider the motion upwards , in this case the gravitational acceleration should be negative in upwards (assume g =10 m/s2 downwards)

that is,

$v^{2}=u^{2} +2as\\0=7.3^{2} -2*10*s\\s=2.6645m$