The term for the bacterium that causes tuberculosis

A cylinder with a piston contains 0.200 mol of oxygen at 2.00×105 Pa and 360 K . The oxygen may be treated as an ideal gas. The

ikadub [295]

Answer:

A. $W=600\ J$

B. $Q=2112\ J$

C. $\Delta U=1512\ J$

D. $W=0\ J$

Explanation:

Given:

no. of moles of oxygen in the cylinder, $n=0.2$

initial pressure in the cylinder, $P_i=2\times 10^5\ Pa$

initial temperature of the gas in the cylinder, $T_i=360\ K$

According to the question the final volume becomes twice of the initial volume.

Using ideal gas law:

$P.V=n.R.T$

$2\times 10^5\times V_i=0.2\times 8.314\times 360$

$V_i=0.003\ m^3$

A.

Work done by the gas during the initial isobaric expansion:

$W=P.dV$

$W=P_i\times (V_f-V_i)$

$W=2\times 10^5\times (0.006-0.003)$

$W=600\ J$

C.

we have the specific heat capacity of oxygen at constant pressure as:

$c_v=21\ J.mol^{-1}.K^{-1}$

Now we apply Charles Law:

$\frac{V_i}{T_i} =\frac{V_f}{T_f}$

$\frac{0.003}{360} =\frac{0.006}{T_f}$

$T_f=720\ K$

Now change in internal energy:

$\Delta U=n.c_p.(T_f-T_i)$

$\Delta U=0.2\times 21\times (720-360)$

$\Delta U=1512\ J$

B.

Now heat added to the system:

$Q=W+\Delta U$

$Q=600+1512$

$Q=2112\ J$

D.

Since during final cooling the process is isochoric (i.e. the volume does not changes). So,

$W=0\ J$

7 0

3 years ago

Sixty identical drippers, each with a hole of diameter 1.00 mm, are used to water a yard. If the water in the main pipe of diame

VashaNatasha [74]

Answer:

a

$V = 5.30 *10^{-2} \ m^3$

b

$v_1 = 0.3127 \ m/s$

Explanation:

From the question we are told that

The number of identical drippers is n = 60

The diameter of each hole in each dripper is $d = 1.0 \ mm = 0.001 \ m$

The diameter of the main pipe is $d_m = 2.5 \ cm = 0.025 \ m$

The speed at which the water is flowing is $v = 3.00 \ cm/s = 0.03 \ m/s$

Generally the amount of water used in one hour = 3600 seconds is mathematically represented as

$V = A * v * 3600$

Here A is the area of the main pipe with value

$A = \pi * \frac{d^2}{4}$

=> $A = 3.142 * \frac{0.025^2}{4}$

=> $A = 0.0004909 \ m^2$

So

=> $V = 0.0004909 * 0.03 * 3600$

=> $V = 5.30 *10^{-2} \ m^3$

Generally the area of the drippers is mathematically represented as

$A_1= n * \pi \frac{d^2}{4}$

=> $A_1 = 60 * 3.142 * \frac{0.001 ^2}{4}$

=> $A_1 = 4.713 *10^{-5} \ m^2$

Generally from continuity equation we have that

$Av = A_1 v_1$

=> $0.0004909 * 0.03 = 4.713 *10^{-5} * v_1$

=> $v_1 = 0.3127 \ m/s$

3 0

3 years ago

An object travels a distance of 56 meters to the right in 7 seconds. What is the object's velocity?

Yakvenalex [24]

Explanation:

Distance travelled (d) = 56 metres

Time taken (t) = 7 seconds

velocity of the object (V)

= d / t

= 56 / 7

= 8 m/s

The velocity of the object is 8 m/s.

Hope it will help :)

8 0

3 years ago

Explain why a fire engine’s siren sounds lower in pitch after the fire engine passes you.

Gnoma [55]

When a sound source is moving toward you, you hear a higher frequency than the source is putting out, and when the source is moving away from you, you hear a lower frequency than the real one. The whole process is called the Doppler effect. It works with light too.

5 0

3 years ago

Read 2 more answers

Sketch a free body diagram for a hot air balloon which is rising off the ground. Indicate the magnitude of the force by utilizin

vaieri [72.5K]

Answer:

F_net = B -W

The forces of action and reaction are the weight of the balloon that is the force of attraction of the Earth and the outside so the balloon pulls the earth that has an upward direction and is applied to the planet

Explanation:

A hot air balloon is subjected to the force of its weight directed towards the center of the Earth. The thrust due to the cold air released, this thrust is directed upwards.

If we assume that the balloon rises at a constant speed

F_net = B -W

F_neta = ρ g V_body - ρ_body g V_body

The forces of action and reaction are the weight of the balloon that is the force of attraction of the Earth and the outside so the balloon pulls the earth that has an upward direction and is applied to the planet

3 0

2 years ago

The term for the bacterium that causes tuberculosis​

The term for the bacterium that causes tuberculosis