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3 years ago

1. what is volume?

Chemistry

2 answers:

bazaltina [42]3 years ago

4 0

Hello!

Answer:

1. D.

2. A.

Explanation:

↓↓↓↓↓↓↓↓↓↓↓

Volume is the amount of space that an object takes up. Volume is constant for solids and liquids; it varies for gases. The volume of an object can be measured in many ways. For a regular solid, use formulas like V=l*w*h or V=B*h. For an irregular solid, use the water displacement method. For a liquid, use a graduated cylinder. Common units for volume include cubic centimeters, milliliters, and liters. Volume is a physical property. Mass is the amount of matter in an object. The mass of an object is constant. Mass is measured with a balance. Common units for mass are grams and kilograms. Hope this helps! Thank you for posting your question at here on brainly. -Charlie

gavmur [86]3 years ago

3 0

1) D) The amount of space a substance takes up
2) A) The amount of matter in a substance

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Metals have high melting and boiling points and are often shiny and silvery. Which of the blocks are metals?

DanielleElmas [232]

Answer:

S and p blocks elements are considered metals while d-block elements are considered transition metals.

Explanation:

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goblinko [34]

According to law of definite proportion:

In a compound, elements are always arranged in fixed ratio by mass.

Here, sample 1 has 23.22 g Carbon and 32.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

$n_{C}=\frac{m_{C}}{M_{C}}=\frac{24.22 g}{12 g/mol}\approx 2 mol$

Similarly, number of moles of oxygen will be:

$n_{O}=\frac{m_{O}}{M_{O}}=\frac{32 g}{16 g/mol}=2 mol$

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Sample 2:

It has 36.22 g Carbon and 48.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

$n_{C}=\frac{m_{C}}{M_{C}}=\frac{36.22 g}{12 g/mol}\approx 3 mol$

Similarly, number of moles of oxygen will be:

$n_{O}=\frac{m_{O}}{M_{O}}=\frac{48 g}{16 g/mol}=3 mol$

The ratio of number of moles of carbon and oxygen will be:

$C:O=n_{C}:n_{O}=3:3=1:1$

The formula of compound will be CO.

Therefore, it is proved that carbon and oxygen are present in fixed ratios in both the samples.

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