Answer:
- 278.34 kg m/s^2
Explanation:
The rate of the change of momentum is the same as the force.
The force that an object feels when moviming in a circular motion is given by:
F = -mrω^2
Where ω is the angular speed and r is the radius of the circumference
Aditionally, the tangential velocity of the body is given as:
v = rω
The question tells us that
v = 25 m/s
r = 7m
mv = 78 kg m/s
Therefore:
m = (78 kg m/s) / (25 m/s) = 3.12 kg
ω = (25 m/s) / (7 m) = 3.57 (1/s)
Now, we can calculate the force or rate of change of momentum:
F = - (3.12 kg) (7 m)(3.57 (1/s))^2
F = - 278.34 kg m/s^2
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Answer:
D.
Explanation:
To solve the exercise it is necessary to apply the concepts related to the Magnetic Field described by Faraday.
The magnetic field is given by the equation:
Where,
Permeability constant
d = diameter
I = Current
For the given problem we have a change in the diameter, twice that of the initial experiment, therefore we define that:
The ratio of change between the two is given by:
Therefore the correct answer is D.
