Distribute
4x+4(less than) -6
Subtract 4 on both side
4x(less than) -10
divide 4 both sides
x(less than)-2.5
(Final answer is bold) Good luck
Answer:
1960 cm^2
Step-by-step explanation:
Surface area:
Area of cross section x 2 = 1/2 x 20 x 21 x 2 = 420 cm^2
Area of slope = 29 x 22 = 638cm^2
Area of base = 22 x 20 = 440cm^2
Area of back = 21 x 22 = 462cm^2
Total Surface area = 462+440+638+420 = 1960cm^2
Hope this helps
<h3>
Answer:</h3>
Any 1 of the following transformations will work. There are others that are also possible.
- translation up 4 units, followed by rotation CCW by 90°.
- rotation CCW by 90°, followed by translation left 4 units.
- rotation CCW 90° about the center (-2, -2).
<h3>
Step-by-step explanation:</h3>
The order of vertices ABC is clockwise, as is the order of vertices A'B'C'. Thus, if reflection is involved, there are two (or some other even number of) reflections.
The orientation of line CA is to the east. The orientation of line C'A' is to the north, so the figure has been rotated 90° CCW. In general, such rotation can be accomplished by a single transformation about a suitably chosen center. Here, we're told there is <em>a sequence of transformations</em> involved, so a single rotation is probably not of interest.
If we rotate the figure 90° CCW, we find it ends up 4 units east of the final position. So, one possible transformation is 90° CCW + translation left 4 units.
If we rotate the final figure 90° CW, we find it ends up 4 units north of the starting position. So, another possible transformation is translation up 4 units + rotation 90° CCW.
Of course, rotation 90° CCW in either case is the same as rotation 270° CW.
_____
We have described transformations that will work. What we don't know is what is in your drop-down menu lists. There are many other transformations that will also work, so guessing the one you have available is difficult.
Answer:

Step-by-step explanation:






<u>FINAL ANSWER</u>

<u><em>In Decimal Form (Rounded to 3 significant figures)</em></u>
<em>x≈-1.24, 3.24</em>
Answer:



Step-by-step explanation:
Number of Men, n(M)=24
Number of Women, n(W)=3
Total Sample, n(S)=24+3=27
Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>
(a)Probability that both appointees are men.

(b)Probability that one man and one woman are appointed.
To find the probability that one man and one woman are appointed, this could happen in two ways.
- A man is appointed first and a woman is appointed next.
- A woman is appointed first and a man is appointed next.
P(One man and one woman are appointed)

(c)Probability that at least one woman is appointed.
The probability that at least one woman is appointed can occur in three ways.
- A man is appointed first and a woman is appointed next.
- A woman is appointed first and a man is appointed next.
- Two women are appointed
P(at least one woman is appointed)

In Part B, 
Therefore:
