All categories

3 years ago

What is the force when an object exerts 15 pascal pressure on a square surface of side 5 meters

Physics

1 answer:

olga55 [171]3 years ago

3 0

Answer:375N

Explanation:

pressure =15 pascal

Length of side =5 m

Area=length x length

Area=5 x 5

Area=25 m^2

Force=pressure x area

Force=15 x 25

Force=375N

You might be interested in

A bar magnet is placed on a table so that the north pole faces right.

Katena32 [7]

The correct answer is C. They are pointing right to left.

Explanation.

A magnet has two poles, a north pole and a south pole. When dealing with magnets, we define the concept of a magnetic field. A magnetic field represents the effect of the magnet on magnetic materials and moving charges in the space around the magnet. For every magnet, the magnetic field lines always point away from the north pole of the magnet towards the south pole. Since the north pole of this magnet faces right, the magnetic field lines point towards the left.

The correct answer is C. They are pointing right to left.

5 0

4 years ago

Read 2 more answers

A quantum system has three states, with energies 0, 1.6 × 10-21, and 1.6 × 10-21, in Joules. It is coupled to an environment wit

xenn [34]

To develop the problem it is necessary to apply two concepts, the first is related to the calculation of average data and the second is the Boltzmann distribution.

Boltzmann distribution is a probability distribution or probability measure that gives the probability that a system will be in a certain state as a function of that state's energy and the temperature of the system. It is given by

$z = \sum\limit_i e^{-\frac{\epsilon_i}{K_0T}}$

Where,

$\epsilon_i =$ energy of that state

k = Boltzmann's constant

T = Temperature

With our values we have that

T= 250K

$k = 1.381*10^{23} m^2 kg s^{-2} K^{-1}$

$\epsilon_1=0J$

$\epsilon_2=1.6*10^{-21}J$

$\epsilon_3=1.6*10^{-21}J$

To make the calculations easier we can assume that the temperature and Boltzmann constant can be summarized as

$\beta = \frac{1}{kT}$

$\beta = \frac{1}{(1.381*10^{23} m^2)(250)}$

$\beta = 2.9*10^{20}J$

Therefore the average energy would be,

$\bar{\epsilon} =\frac{\sum \epsilon_i e^{-\beta \epsilon_i}}{\sum e^{-\beta \epsilon_i}}$

Replacing with our values we have

$\bar{\epsilon} = \frac{0e^{-0}+1.6*10^{-21}*e^{-\Beta(1.6*10^{-21})}+1.6*10^{-2-1}*e^{-(2.9*10^{20})(1.6*10^{-21})}}{1+2e^{-2.9*10^{20}*1.6*10^{-21}}}$

$\bar{\epsilon} = 0.9*10^{-22}J$

Therefore the average internal energy is $\bar{\epsilon} = 0.9*10^{-22}J$

3 0

3 years ago

A simple pendulum on the surface of Earth is found to undergo 15.0 complete small‑amplitude oscillations in 8.75 s. Find the pen

FinnZ [79.3K]

Answer:

Length of the Pendulum is 14.4 cm

Explanation:

Time period of simple pendulum is given by

$T=2\pi \sqrt{\frac{L}{g} } \\$

time taken for one oscillation is

$T=\frac{time taken}{oscillations} \\T=\frac{8.75}{15} \\T=0.583 s$

Pendulum length on the earth surface is

$L=\frac{T^2g}{4\pi^2 }\\L=\frac{0.583\times 9.8}{4\pi^2 } \\L=0.144 m$

Length of the Pendulum is 14.4 cm

6 0

4 years ago

In order to do work, the force vector must be

aliina [53]

in the same direction as the displacement vector and the motion

5 0

3 years ago

Why are Murcury, venus, earth and mars called the "terrestrial" planets?

Fittoniya [83]

Mercury, Venus, Earth, and Mars are considered terrestrial planets because those planets are mainly composed of metal or rock and are closest to the sun.

5 0

3 years ago