[HELP!! GIVING 40 POINTS]Consider the function f(x)=2x+6, create a situation that would model this function.
1 answer:
(Above is the graph for the line)
Situation:
You are signing up for a book club. The get-in price is 6. Every month, you have to pay 2 dollars.
How This Works:
y=mx+b
M=Slope
B=y intercept.
Y intercept is the starting point. The beginning out. In this case, the y intercept is 6. So, in our situation, 6 is the joining fee. The beginning amount. Slope is the the rate of change. The slope in this problem is 2. Since the monthly fee is 2, that would make it the slope
Situation:
You are signing up for a book club. The get-in price is 6. Every month, you have to pay 2 dollars.
How This Works:
y=mx+b
M=Slope
B=y intercept.
Y intercept is the starting point. The beginning out. In this case, the y intercept is 6. So, in our situation, 6 is the joining fee. The beginning amount. Slope is the the rate of change. The slope in this problem is 2. Since the monthly fee is 2, that would make it the slope
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<u>Correct </u><u>Inputs </u><u>:-</u>
In ΔABC right angled at A, D and E are points on BC, C such that BD = CD and AD ⊥ BC
Let us know about definition of altitude first. The altitude of a triangle is the perpendicular line segment drawn from the vertex to the opposite side of the triangle.
Median is the line segment from a vertex to the midpoint of the opposite side.
<u>Let us Check all options one by one </u>
- CD is line segment which starts from vertex C but don't falls on opposite side AB thus it is not an altitude.❌
- BA is line segment which starts from vertex B and falls perpendicularly on opposite sides AC and is thus an altitude.✔️
- AD is line segment which starts from vertex A and falls perpendicularly on opposite side BC and is thus an altitude.✔️
- AE is a line segment which starts from vertex A but doesn't falls perpendicularly on opposite side BC and is thus not an altitude.❌
- AD falls on BC with D as mid point because BD = CD and is thus a median. ✔️