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mr Goodwill [35]
3 years ago
11

Which statement is false?

Physics
2 answers:
lions [1.4K]3 years ago
6 0

Answer:

its B :)

Explanation:

Mkey [24]3 years ago
3 0

Answer:

Once you reach adulthood, you will not experience peer pressure.

Explanation:

We tend to believe that self-control comes from within, but many of our attitudes depend as much on friends and family as on ourselves. That's because at any stage of our life (even the adult stage) our friends and our family have the power to influence us, sometimes that influence is good and sometimes bad, it's up to us to reason about them.

The people around us have the power to make us fat, consume more alcohol, worry less about the environment and expose ourselves to the sun without proper protection, among many other things.

It is not simply about peer pressure, where you deliberately act in a certain way to suit the group. It is, in fact, largely an unconscious attitude. Without your awareness, your brain is constantly picking up cues from people around you to dictate your behavior. And the consequences can be serious.

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plate tectonics

Explanation:

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If a big truck in front of your car begins to turn left, but its right turn signals are flashing, it is most likely that truck d
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Everyone is trying to living a perfect life via social media.
Stells [14]

Answer:

wdym?

is this a question?

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The orbital motion of Earth around the Sun leads to an observable parallax effect on the nearest stars. For each star listed, ca
Murrr4er [49]

Answer:

Following are the answer to this question:

Explanation:

Formula:

D(PC) =\frac{1}{parallax}\\\\D(av)=D(PC) \times 20.626\ J

Calculating point A:

when the value is 0.38

\to 0.38 \toD(PC)= \frac{1}{0.38}\\\\

                   =2.632

\to D(a.v) = \frac{1}{0.38} \times 206265\\

               =542,802.6

Calculating point B:

when the value is 0.75

\to D(PC)=\frac{1}{0.75}

                =1.33

\to D(a.v) = \frac{1}{0.75} \times 206265\\

             =275,020

Calculating point C:

when the value is 0.28

\to D(PC)=\frac{1}{0.28}

                =3.571

\to D(a.v) = \frac{1}{0.28} \times 206265\\

               =736660.7

Calculating point D:

when the value is 0.42

\to D(PC)=\frac{1}{0.42}

                =2.38

\to D(a.v) = \frac{1}{0.42} \times 206265\\

               =490910.7

Calculating point E:

when the value is 0.31

\to D(PC)=\frac{1}{0.31}

                =3.226

\to D(a.v) = \frac{1}{0.31} \times 206265\\

               =665370.97

6 0
3 years ago
An astronaut circling the earth at an altitude of 400 km is horrified to discover that a cloud of space debris is moving in the
elena-14-01-66 [18.8K]

One of the essential concepts to solve this problem is the utilization of the equations of centripetal and gravitational force.

From them it will be possible to find the speed of the body with which the estimated time can be calculated through the kinematic equations of motion. At the same time for the calculation of this speed it is necessary to clarify that this will remain twice the ship, because as we know by relativity, when moving in the same magnitude but in the opposite direction, with respect to the ship the debris will be double speed.

By equilibrium the centrifugal force and the gravitational force are equal therefore

F_c = F_g

\frac{mv^2_{orbit}}{r} = \frac{GMm}{r^2}

Where

m = mass spacecraft

v = velocity

G = Gravitational Universal Constant

M = Mass of earth

r \rightarrow R+h \Rightarrow Radius of earth and orbit

Re-arrange to find the velocity

\frac{mv^2_{orbit}}{r} = \frac{GMm}{r^2}

\frac{v^2_{orbit}}{r} = \frac{GM}{r^2}

v^2_{orbit}=\frac{GM}{r}

v_{orbit} = \sqrt{\frac{GM}{r}}

v_{orbit} = \sqrt{\frac{GM}{R+h}}

Replacing with our values we have

v_{orbit} = \sqrt{\frac{(6.67*10^{-11})(5.98*10^{24})}{6.37*10^6+0.4*10^6}}

v_{orbit} = 7676m/s

From the cinematic equations of motion we have to

t = \frac{d}{2v_{orbit}} \rightarrow Remember that the speed is double for the counter-direction of the trajectories.

Replacing

t = \frac{29000m}{7676m/s}

t = 3.778s

Therefore the time required is 3.778s

4 0
3 years ago
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