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Colt1911 [192]
3 years ago
6

Secondclass lever short note​

Physics
2 answers:
Artist 52 [7]3 years ago
7 0

Answer:

second

Explanation:

seraphim [82]3 years ago
6 0

Answer:

wow

Explanation:

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the thermometer has its stem marked in millimeter instead of degree Celsius. the lower fixed point is 30mm and the upper fixed p
Lorico [155]

10°c

Explanation:

Given parameter;

Lower fixed point = 30mm

Upper fixed point = 180mm

Reading = 45mm

Unknown:

The degree celcuis temperature at 45mm = ?

Solution:

To solve this problem we simply compare the mm- scale to the celcius - scale that we know.

The upper fixed point is the boiling point of water

Lower fixed point is the freezing point of water

This shows that both the upper and lower fixed point of both thermometers are the same;

         mm-scale          °c scale

          180mm               100°c

            45mm                x

          30mm                  0°c

Solving;

                     \frac{x - 0}{100 -0} =  \frac{45 - 30 }{180- 30}

   x (150) = 100  x 15

   x = 10°c

learn more:

Temperature scales brainly.com/question/1603430

#learnwithBrainly

 

7 0
3 years ago
Newton's law of cooling is , where is the temperature of an object, is in hours, is a constant ambient temperature, and is a pos
kirill [66]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The time taken  is  t  = 6.89 \ hrs

 

Explanation:

From the question we are told that

       The value of  k = 0.15hr^{-1}

       The  the interior temperature is  u(t = 0) =  70 ^oF

         The external temperature is  T  = 11 ^oF

          The required interior temperature is  u_{t} = 32 ^oF

      The newton cooling law is

                      \frac{du}{dt}  =  -k (u -T)

=>                 \frac{du}{u-T}  = - kdt

  Now integrate both sides we have  

                 \int\limits \frac{du}{u-T}  =\int\limits   - kdt

                   ln (u - T) =  -kt + c    

Since c is a constant lnC = c   will also give a constant so

                 ln (u - T) =  -kt + ln C    

       =>       \frac{(u -T)}{C}  =  e^{-kt}

     =>        u = T + Ce^{-kt}  

          substituting value

                  70 = 11 +Ce^{-0* 0.15}

                  C = 59

Hence

        u_t =  11 + 59 e^{-0.15 *t}

       32=  11 + 59 e^{-0.15 *t}

=>     t  =  -\frac{ln(\frac{21}{59} )}{0.15}

         t  = 6.89 \ hrs

 

3 0
3 years ago
A 0.0450-kg golf ball initially at rest is given a speed of 25.0 m/s when a club strikes. If the club and ball are in contact fo
LuckyWell [14K]

Answer:

Average force, F = 562.5 N

Explanation:

Mass of the golf ball, m = 0.045 kg

Initially, it is at rest, u = 0

Final speed of the ball, v = 25 m/s

The club and the ball are in contact for, t=2\ ms=2\times 10^{-3}\ s

We need to find the average force acting on the ball. It can be calculated using the formula as :

F\times t=m(v-u)

F=m\dfrac{v-u}{t}

F=0.045\times \dfrac{25}{2\times 10^{-3}}  

F = 562.5 N

So, the average force acting on the ball is 562.5 N. Hence, this is the required solution.

5 0
3 years ago
I need help with...
Rom4ik [11]
The car will gain new momentum if it's velocity is doubled or tripled.
6 0
3 years ago
Choose the nonmetallic elements from the list. Check all that apply.
NikAS [45]
Polonium, gallium,argon
3 0
3 years ago
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