Name four products of incomplete combustion Which 4? 1. 2. 3. 4.

How do you balance this Chemical Equation? C5H12O + O2 = CO2 + H2O

ICE Princess25 [194]

Answer:

The chemical equation by putting, a 2 on C₅H₁₂O, 15 on O₂, 10 on CO₂ , and 12 on H₂O in the equation;

2C₅H₁₂O + 15O₂ → 10CO₂ + 12H₂O

Explanation:

Chemical equations are balanced by putting coefficients on the reactants and products to ensure the total number of atoms on the left side equal to those on the right side.
Balancing chemical equations is done to make chemical equations obey the law of conservation of mass.
According to the law of conservation of mass, the mass of the reactants should always be equal to the mass of products.
This is done by balancing chemical equations to ensure the total number of atoms on the left side is equal to that on the right side.

Therefore, the balanced equation is;

2C₅H₁₂O + 15O₂ → 10CO₂ + 12H₂O

3 0

3 years ago

A 1.00 g sample of octane (C8H18) is burned in a bomb calorimeter with a heat capacity of 837J∘C that holds 1200. g of water at

lubasha [3.4K]

Answer:

The heat of combustion for 1.00 mol of octane is -5485.7 kJ/mol

Explanation:

Step 1: Data given

Mass of octane = 1.00 grams

Heat capacity of calorimeter = 837 J/°C

Mass of water = 1200 grams

Temperature of water = 25.0°C

Final temperature : 33.2 °C

Step 2: Calculate heat absorbed by the calorimeter

q = c*ΔT

⇒ with c = the heat capacity of the calorimeter = 837 J/°C

⇒ with ΔT = The change of temperature = T2 - T1 = 33.2 - 25.0 : 8.2 °C

q = 837 * 8.2 = 6863.4 J

Step 3: Calculate heat absorbed by the water

q = m*c*ΔT

⇒ m = the mass of the water = 1200 grams

⇒ c = the specific heat of water = 4.184 J/g°C

⇒ ΔT = The change in temperature = T2 - T1 = 33.2 - 25 = 8.2 °C

q = 1200 * 4.184 * 8.2 = 41170.56 J

Step 4: Calculate the total heat

qcalorimeter + qwater = 6863.4 + 41170. 56 = 48033.96 J = 48 kJ

Since this is an exothermic reaction, there is heat released. q is positive but ΔH is negative.

Step 5: Calculate moles of octane

Moles octane = 1.00 gram / 114.23 g/mol

Moles octane = 0.00875 moles

Step 6: Calculate heat combustion for 1.00 mol of octane

ΔH = -48 kJ / 0.00875 moles

ΔH = -5485.7 kJ/mol

The heat of combustion for 1.00 mol of octane is -5485.7 kJ/mol

8 0

2 years ago

A substance that can be broken down into simpler subtend only by a chemical change is aa. homogenous mixtureb. heterogeneous mix

Natasha2012 [34]

Answer:

d. compound

Explanation:

Mixture : It is defined as the substance that is made by the combination of two or more different components which are physically combined.

Homogeneous mixture are the mixtures in which the composition of the substances in it are uniformly mixed. Heterogeneous mixture are the mixtures in which the composition of the substances in it are not uniformly mixed.

Compound : It is a pure substance which is made from atoms of different elements combined together in a fixed ratio by mass and are chemically bonded.

Element : It is a pure substance which is composed of atoms of similar elements.

As discussed above, The different elements in the compounds are chemically bonded and hence, it is the substance which can be broken down into the simpler units when it subtend only by the chemical change.

3 0

3 years ago

How many atoms are there in each of the following ?a.)1.50 mol Na c.) 0.250 mol. Sib.)6.755 mol Pb

tamaranim1 [39]

$a) \: n = \frac{N}{NA} \\ 1.5 = \frac{x}{6.02 \times \: {10}^{23} } \\ x = 1.5 \times 6.02 \times {10}^{23} \\ x = 9.03 \times {10}^{23} \: atoms \: of \: Na$

$b) \: n = \frac{N}{NA} \\ 0.25 = \frac{x}{6.02 \times \: {10}^{23} } \\ x = 0.25 \times 6.02 \times {10}^{23} \\ x = 1.505 \times {10}^{23} \: atoms \: of \: Si \:$
$c) \: n = \frac{N}{NA} \\ 6.755 = \frac{x}{6.02 \times \: {10}^{23} } \\ x = 6.755 \times 6.02 \times {10}^{23} \\ x = 40,6651 \times {10}^{23} \\ x = 4.07 \times {10}^{24} \: atoms \: of \: Pb \:$

5 0

3 years ago

A solution is made by adding 20 g table salt to 100 mL water. The solubility of salt is 36 g/100 mL water. Which term best descr

marysya [2.9K]

Answer:

We say that the solution is unsaturated.

Explanation:

If the salt solubility is 36 g in 0.1 L of water then we can dissolve 360 g of salt in 1 L of water.

Because the solution contains 200 g of salt in 1 L of water, the solution is unsaturated because more salt can be added until we reach the saturation point.

We call the solution dilute when we compare the concentration of a solution with the concentration of another solution, but here we do not compare different solutions.

3 0

2 years ago

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