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Svetllana [295]
2 years ago
5

Carbon dioxide enters an adiabatic compressor at 100 kPa and 300 K at a rate of 0.5 kg/s and leaves at 600 kPa and 450 K. Neglec

ting kinetic energy changes, determine (a) the volume flow rate of the carbon dioxide at the compressor inlet and (b) the power input to the compressor. Amswers: (a) 0.283 m^3/s, (b) 68.8 kW
Chemistry
1 answer:
Sergeeva-Olga [200]2 years ago
5 0

Answer:

(a) Q_1=0.283m^3/s

(b) W=68.8kW

Explanation:

Hello,

(a) Based on the inlet conditions, we see that such carbon dioxide has an ideal behavior, so the inlet specific volume is:

v_1=\frac{RT}{PM}=\frac{8.314\frac{Pa*m^3}{mol*K}*300K}{100000Pa*44g/mol} =0.000567m^3/kg

Thus, the volumetric flow rate turns out:

Q_1=0.000567m^3/g*0.5kg/s*1000=0.283m^3/s

(b) Now, by writing and energy balance we have:

mh_1+W=mh_2

Thus, since the ideal gas enthalpy does not depend on the pressure, in Cengel's A-20 table, the corresponding enthalpies at 300K and 450 K are 9431kJ/kmol and 15483kJ/kmol whose values in kJ/kg are 214.34 kJ/kg and 351.89 kJ/kg respectively, thus:

W=0.5kg/s*(351.89-214.34)kJ/kg=68.8kW

Best regards.

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Moles = 23.53/40.64

= 0.5789 moles

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Calculate the molarity of a solution prepared by dissolving 0.2 mol sucrose in enough water to make a 100 ml solution.
Lelechka [254]

Taking into account the definition of molarity, the molarity of a solution prepared by dissolving 0.2 mol sucrose in enough water to make a 100 mL solution is 2 \frac{moles}{liter}.

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

molarity=\frac{number of moles}{volume}

Molarity is expressed in units \frac{moles}{liter}.

<h3>Molarity in this case</h3>

In this case, you have:

  • number of moles= 0.2 moles
  • volume= 100 mL= 0.1 L

Replacing in the definition of molarity:

molarity=\frac{0.2 mole}{0.1 L}

Solving:

<u><em>molarity= 2 </em></u>\frac{moles}{liter}

Finally, the molarity of a solution prepared by dissolving 0.2 mol sucrose in enough water to make a 100 mL solution is 2 \frac{moles}{liter}.

Learn more about molarity:

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8 0
2 years ago
The reaction C 4 H 8 ( g ) ⟶ 2 C 2 H 4 ( g ) C4H8(g)⟶2C2H4(g) has an activation energy of 262 kJ / mol. 262 kJ/mol. At 600.0 K,
ludmilkaskok [199]

Answer: 4.3\times 10^{-13}s^{-1}

Explanation:

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

or,

\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = rate constant at 600.0K = 6.1\times 10^{-8}s^{-1}

K_2 = rate constant at 775.0 = ?

Ea = activation energy for the reaction = 262 kJ/mol = 262000J/mol

R = gas constant = 8.314 J/mole.K

T_1 = initial temperature = 600.0K

T_2 = final temperature = 775.0K

Now put all the given values in this formula, we get

\log (\frac{6.1\times 10^{-8}}{K_2})=\frac{262000}{2.303\times 8.314J/mole.K}[\frac{1}{600.0K}-\frac{1}{775.0K}]

\log (\frac{6.1\times 10^{-8}s^}{K_2})=5.150

(\frac{6.1\times 10^{-8}}{K_2})=141253.8

Therefore, the value of the rate constant at 775.0 K is 4.3\times 10^{-13}s^{-1}

5 0
2 years ago
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