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ehidna [41]
3 years ago
5

A vehicle travels 53 km both north and east. What is the vehicle's displacement?

Physics
1 answer:
gizmo_the_mogwai [7]3 years ago
8 0

75km

I dont really know how to do the math but thats what my teacher told me when i asked

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Because it reverses an image there for making the objects appear on opposite side
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3 years ago
Which best describes the surface of a concave mirror? It is flat. It is textured. It curves outward. It curves inward.
Sonja [21]

The concave mirror is a spherical-shaped mirror that has an inner curved surface. Hence, option (4) is correct.

What is a concave mirror?

The concave mirrors are spherical-shaped mirrors that are painted on the outward surface. It is also known as the converging mirror, having the recessed inner reflecting surface.

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  • The reflecting surface of the concave mirror has its vertex or midpoint lying farther away from the objects than the edges.

Thus, we can conclude that the surface of the concave mirror is curved inward. Hence, option (4) is correct.

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2 years ago
A 5.0 kg box slides down a 4.0 m long ramp that makes a 25 angle with the ground. If the coefficient of kinetic friction is 0.65
Sedaia [141]

The thermal energy was produced is 116J

<h3>What is the thermal energy produced?</h3>

Now we know that the frictional force produces the energy that is lost as heat as the body slides down the incline. The magnitude of the frictional force is obtained from;

Ff= μmgcosθ

Ff =  0.65 *  5.0 kg * 9.8 m/s^2 * cos 25

Ff = 29 N

Hence, the thermal energy is;

29 N * 4.0 m = 116J

Learn more about frictional force:brainly.com/question/1714663

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4 0
2 years ago
Which of these would be best explained by the Doppler effect? A) The change in frequency as you shorten a guitar string. B) The
Lady_Fox [76]

B)

Doppler effect is about the apparent change in frequency. The change in pitch heard as an ambulance approaches you is an example of this

4 0
3 years ago
An observer stands on the side of the front of a stationary train. When the train starts moving with constant acceleration, the
Zarrin [17]

To solve this problem we will use the linear motion description kinematic equations. We will proceed to analyze the general case by which the analysis is taken for the second car and the tenth. So we have to:

x = v_0 t \frac{1}{2} at^2

Where,

x= Displacement

v_0 = Initial velocity

a = Acceleration

t = time

Since there is no initial velocity, the same equation can be transformed in terms of length and time as:

L = \frac{1}{2} a t_1 ^2

For the second cart

2L \frac{1}{2} at_2^2

When the tenth car is aligned the length will be 9 times the initial therefore:

9L = \frac{1}{2} at_3^2

When the tenth car has passed the length will be 10 times the initial therefore:

10L = \frac{1}{2}at_4^2

The difference in time taken from the second car to pass it is 5 seconds, therefore:

t_2-t_1 = 5s

From the first equation replacing it in the second one we will have that the relationship of the two times is equivalent to:

\frac{1}{2} = (\frac{t_1}{t_2})^2

t_1 = \frac{t_2}{\sqrt{2}}

From the relationship when the car has passed and the time difference we will have to:

(t_2-\frac{t_2}{\sqrt{2}}) = 5

t_2 (\sqrt{2}-1) = 3\sqrt{2}

t_2= (\frac{5\sqrt{2}}{\sqrt{2}-1})^2

Replacing the value found in the equation given for the second car equation we have to:

\frac{L}{a} = \frac{1}{4} (\frac{5\sqrt{2}}{\sqrt{2}-1})^2

Finally we will have the time when the cars are aligned is

18 \frac{1}{4} (\frac{5\sqrt{2}}{\sqrt{2}-1})^2 = t_3^2

t_3 = 36.213s

The time when you have passed it would be:

20\frac{1}{4} (\frac{5\sqrt{2}}{\sqrt{2}-1})^2 = t_4^2

t_4 = 38.172

The difference between the two times would be:

t_4-t_3 = 38.172-36.213 \approx 2s

Therefore the correct answer is C.

4 0
3 years ago
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