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Otrada [13]
3 years ago
9

NaCl(aq) AgNO3(aq) → AgCl(s) NaNO3(aq) : NaCl(aq) AgNO3(aq) \rightarrow AgCl(s) NaNO3(aq) : blank H2SO4(aq) 2 LiOH(aq) → 2 H2O(l

) Li2SO4(aq) : H2SO4(aq) 2 LiOH(aq) \rightarrow 2 H2O(l) Li2SO4(aq) : blank HCl(aq) (NH4)2S(aq) → H2S(g) 2 NH4Cl(aq) : HCl(aq) (NH4)2S(aq) \rightarrow H2S(g) 2 NH4Cl(aq) : blank Mg(s) Cu(NO3)2(aq) → Mg(NO3)2(aq) Cu(s) :
Chemistry
1 answer:
Elena L [17]3 years ago
8 0

The question is incomplete, here is a complete question.

Categorize each reaction into types of chemical reactions.

(1) NaCl(aq)+AgNO_3(aq)\rightarrow AgCl(s)+NaNO_3(aq)

(2) H_2SO_4(aq)+2LiOH(aq)\rightarrow 2H_2O(l)+Li_2SO_4(aq)

(3) HCl(aq)+(NH_4)_2S(aq)\rightarrow H_2S(g)+2NH_4Cl(aq)

(4) Mg(s)+Cu(NO_3)_2(aq)\rightarrow Mg(NO_3)_2(aq)+Cu(s)

Answer :

(1) Precipitation reaction

(2) Neutralization reaction

(3) Double-displacement reaction

(4) Single replacement reaction

Explanation :

(1) The balanced chemical reaction is:

NaCl(aq)+AgNO_3(aq)\rightarrow AgCl(s)+NaNO_3(aq)

This reaction is a precipitation reaction in which an insoluble salt formed when two aqueous solutions are combined.  The insoluble salt that settle down in the solution is known an precipitate.

(2) The balanced chemical reaction is:

H_2SO_4(aq)+2LiOH(aq)\rightarrow 2H_2O(l)+Li_2SO_4(aq)

This is a neutralization reaction in which an acid react with a base react to give salt and water as a product that means it reacts to give a neutral solution.

(3) The balanced chemical reaction is:

HCl(aq)+(NH_4)_2S(aq)\rightarrow H_2S(g)+2NH_4Cl(aq)

The given reaction is a double-displacement reaction in which the cation of two reactants molecule exchange their places to give two different products.

(4) The balanced chemical reaction is:

Mg(s)+Cu(NO_3)_2(aq)\rightarrow Mg(NO_3)_2(aq)+Cu(s)

This reaction is a single replacement reaction in which the the more reactive element replace the less reactive element.

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Determine which of the following contains the greatest mass of aluminium: 122 g of AlPO4, 266 g of A12C16, or 225 g of
pav-90 [236]

Answer : The Al_2S_3 contains the greatest mass of aluminum.

Explanation :

<u>For AlPO_4 :</u>

Molar mass of AlPO_4 = 122 g/mole

Molar mass of aluminium = 27 g/mole

As, 122 g of AlPO_4 contains 27 g of Al

So, 122 g of AlPO_4 contains \frac{122}{122}\times 27=27g of Al

The mass of 'Al' in AlPO_4 is, 27 grams.

<u>For Al_2Cl_6 :</u>

Molar mass of Al_2Cl_6 = 266.7 g/mole

Molar mass of aluminium = 27 g/mole

As, 266.7 g of Al_2Cl_6 contains 2\times 27g of Al

So, 266 g of Al_2Cl_6 contains \frac{266}{266.7}\times 2\times 27=54g of Al

The mass of 'Al' in Al_2Cl_6 is, 54 grams.

<u>For Al_2S_3 :</u>

Molar mass of Al_2S_3 = 150 g/mole

Molar mass of aluminium = 27 g/mole

As, 150 g of Al_2S_3 contains 2\times 27g of Al

So, 225 g of Al_2S_3 contains \frac{225}{150}\times 2\times 27=81g of Al

The mass of 'Al' in Al_2S_3 is, 81 grams.

Hence, from this we conclude that Al_2S_3 contains the greatest mass of aluminum.

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3 years ago
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3 years ago
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HELPP ME PLEASE!! What would be the density of a 40 g object that displaces 10 ml of water?
Snezhnost [94]

Answer:

<h2>The answer is 4.0 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 40 g

volume = 10 mL

The density of the object is

density =  \frac{40}{10}  = 4 \\

We have the final answer as

<h3>4.0 g/mL</h3>

Hope this helps you

5 0
3 years ago
Nitrogen (N2) enters a well-insulated diffuser operating at steady state at 0.656 bar, 300 K with a velocity of 282 m/s. The inl
Tasya [4]

Answer:

  1. The exit temperature of the Nitrogen would be 331.4 K.
  2. The area at the exit of the diffuser would be 7*10^{-3} m^2.
  3. The rate of entropy production would be 0.

Explanation:

  1. First it is assumed that the diffuser works as a isentropic device. A isentropic device is such that the entropy at the inlet is equal that the entropy T the exit.
  2. It will be used the subscript <em>1 for the</em> <em>inlet conditions of the nitrogen</em>, and the subscript <em>2 for the exit conditions of the nitrogen</em>.
  3. It will be called: <em>v</em> the velocity of the nitrogen stream, <em>T</em> the nitrogen temperature, <em>V</em> the volumetric flow of the specific stream, <em>A</em> the area at the inlet or exit of the diffuser and, <em>P</em> the pressure of the nitrogen flow.
  4. It is known that <em>for a fluid flowing, its volumetric flow is obtain as:</em> V=v*A,
  5. Then for the inlet of the diffuser: V_1=v_1*A_1=282\frac{m}{s}*4.8*10^{-3}m^2=1.35\frac{m^3}{s}
  6. For an ideal gas working in an isentropic process, it follows that: \frac{T_{2} }{T_1}=(\frac{P_2}{P_1})^k where each variable is defined according with what was presented in step 2 and 3, and <em>k </em>is the heat values relationship, 1.4 for nitrogen.
  7. Then <em>solving</em> for T_2, the temperature of the nitrogen at the exit conditions: T_2=T_1(\frac{P_2}{P_1})^k then, T_2=300 K (\frac{0.9 bar}{0.656 bar})^{(\frac{1.4-1}{1.4})}=331.4 K
  8. Also, for an ideal gas working in an isentropic process, it follows that:  \frac{P_2}{P_1}= (\frac{V_1}{V_2})^k, where each variable is defined according with what was presented in step 2 and 3, and <em>k</em> is the heat values relationship, 1.4 for nitrogen.
  9. Then <em>solving</em> for V_2 the volumetric flow at the exit of the diffuser: V_2=V_1*\frac{1}{\sqrt[k]{\frac{P_2}{P_1}}}=\frac{1.35\frac{m^3}{s}}{\sqrt[1.4]{\frac{0.9bar}{0.656bar} }}=1.080\frac{m^3}{s}.
  10. Knowing that V_2=1.080\frac{m^3}{s}, it is possible to calculate the area at the exit of the diffuser, using the relationship presented in step 4, and solving for the required parameter: A_2=\frac{V_2}{v_2}=\frac{1.08\frac{m^3}{s} }{140\frac{m}{s}}=7.71*10^{-3}m^2.
  11. <em>To determine the rate of entropy production in the diffuser,</em> it is required to do a second law balance (entropy balance) in the control volume of the device. This balance is: S_1+S_{gen}-S_2=\Delta S_{system}, where: S_1 and S_2 are the entropy of the stream entering and leaving the control volume respectively, S_{gen} is the rate of entropy production and, \Delta S_{system} is the change of entropy of the system.
  12. If the diffuser is operating at stable state is assumed then \Delta S_{system}=0. Applying the entropy balance and solving the rate of entropy generation: S_{gen}=S_2-S_1.
  13. Finally, it was assume that the process is isentropic, it is: S_1=S_2, then S_{gen}=0.
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3 years ago
In June there are fewer hours of daylight and less direct sunlight in the
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Your answer is <em>Southern Hemisphere</em><em></em>.

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