The Law of Conservation of Mass states that the mass of reactants entering a reaction must be equal to the mass of the products exiting it. In this case, we only have 2 reactants, Fe and S, and we only have 1 product, FeS. Therefore we expect the total mass of the Fe and S reactants to equal the mass of FeS. This gives us 112 g + 64 g = 176 g of FeS, which is choice D.
Iodine would have chemical properties most like Fluorine, Chlorine and other elements in group 7
<u>Solution and Explanation:</u>
[La3+] = 0.1 M
<u>At the equilibrium:
</u>
La(IO3)3 <----> La3+ + 3 IO3-
0.1 +s 3s
![\mathrm{Ksp}=[\mathrm{La} 3+][\mathrm{IO} 3-]^{\wedge} 3](https://tex.z-dn.net/?f=%5Cmathrm%7BKsp%7D%3D%5B%5Cmathrm%7BLa%7D%203%2B%5D%5B%5Cmathrm%7BIO%7D%203-%5D%5E%7B%5Cwedge%7D%203)
Since Ksp is small, s can be ignored as compared to the 0.1
The above shown expression thus becomes:
<u>Answer: 1.4*10^-4 M
</u>
Explanation:
The substance(s) to the left of the arrow in a chemical equation are called reactants. A reactant is a substance that is present at the start of a chemical reaction. The substance(s) to the right of the arrow are called products . A product is a substance that is present at the end of a chemical reaction
The answer would look something like this. (sorry for the ugliest diagram ever.)
