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4 years ago

Why is the unit of temperature is called derived unit

Physics

1 answer:

Vadim26 [7]4 years ago

3 0

Explanation:

The SI unit of power is the kilogram-meter2 per second cubed, which is called the watt (1 W = 1 kg-m2/s3). Since power is the energy used per unit of time, it is derived as the energy/time quotient.

Kelvin is a fundamental unit! It's a lot easier to measure temperature than to measure the motion of component particles. Hence, we can accept it as a fundamental quantity. Time is said to be a fundamental unit because it is not dependent on one or more units

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An object is dropped on Earth from a height of 15 m. What is the magnitude of the velocity of the object just as it hits the gro

ivolga24 [154]

Here, we know, according to 3rd Equation of Kinematics,
v² - u² = 2as

Here, u = 0 [ Free fall ]
a = 9.8 m/s² [ constant value for the Earth system ]
s = 15 m

Substitute their values,
v² - 0² = 2 * 9.8 * 15
v² = 294
v = √294
v = 17.15 m/s

In short, Your Answer would be Option D

Hope this helps!

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3 years ago

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<h2>The correct option is C</h2>

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3 years ago

A merry-go-round with a rotational inertia of 600 kg m2 and a radius of 3. 0 m is initially at rest. A 20 kg boy approaches the

Margaret [11]

Hi there!

$\boxed{\omega = 0.38 rad/sec}$

We can use the conservation of angular momentum to solve.

$\large\boxed{L_i = L_f}$

Recall the equation for angular momentum:

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We can begin by writing out the scenario as a conservation of angular momentum:

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$\omega_m$ = angular velocity of merry go round (rad/sec)

$\omega_f$ = final angular velocity of COMBINED objects (rad/sec)

$I_b$ = moment of inertia of boy (kgm²)

$\omega_b$ = angular velocity of the boy (rad/sec)

The only value not explicitly given is the moment of inertia of the boy.

Since he stands along the edge of the merry go round:

$I = MR^2$

We are given that he jumps on the merry-go-round at a speed of 5 m/s. Use the following relation:

$\omega = \frac{v}{r}$

$L_b = MR^2(\frac{v}{R}) = MRv$

Plug in the given values:

$L_b = (20)(3)(5) = 300 kgm^2/s$

Now, we must solve for the boy's moment of inertia:

$I = MR^2\\I = 20(3^2) = 180 kgm^2$

Use the above equation for conservation of momentum:

$600(0) + 300 = \omega_f(180 + 600)\\\\300 = 780\omega_f\\\\\omega = \boxed{0.38 rad/sec}$

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Answer:

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Why is the unit of temperature is called derived unit​

Why is the unit of temperature is called derived unit